- #1

hermanni

- 25

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Prove that if p is a prime and P is a subgroup of S(p) of order p, then

| N (P) | = p(p-1). (Argue that every conjugate of P contains exactly p-1 p-cycles and use the formula for the number of p-cycles to compute the index of

N(P) in S(p) .

N(P) : normalizer of P in S(p).

I reaaly have no clue , can someone help??