Proving Open/Closed Sets: Functional Analysis in C [0,1]

Click For Summary
SUMMARY

The discussion focuses on proving that specific sets in the space of continuous functions C[0,1] with the sup metric are open and closed. The set A, defined as A={g Є C[0,1]: d(g,f) > 3}, is established as an open set, while the set B, defined as B={g Є C[0,1]: 1 ≤ d(g,f) ≤ 3}, is confirmed as a closed set. The function f is given by f(x)=x²+2, and the distance d(f,g) represents the maximum distance between the two continuous functions. Visualizing the graph of f is recommended as a strategy for understanding these properties.

PREREQUISITES
  • Understanding of functional analysis concepts, specifically open and closed sets.
  • Familiarity with the sup metric in the context of continuous functions.
  • Basic knowledge of continuous functions and their properties.
  • Ability to sketch graphs of functions to visualize mathematical concepts.
NEXT STEPS
  • Study the properties of open and closed sets in metric spaces.
  • Learn about the sup metric and its implications for continuous functions.
  • Explore examples of proving sets are open or closed in functional analysis.
  • Practice sketching graphs of functions to better understand their behavior and properties.
USEFUL FOR

Students and researchers in mathematics, particularly those studying functional analysis, as well as educators looking for examples of open and closed sets in continuous function spaces.

patricia-donn
Messages
5
Reaction score
0
Hello
Would anyone out there be able to help me with a problem I'm having? I have to prove that a function is open and that another is closed. The question is:

Consider C [0,1] with the sup metric. Let f:[0,1]→R be the function given by f(x)=x²+2
Let A={g Є C[0,1]: d(g,f) > 3}. Prove that A is an open set
Let B={g Є C[0,1]: 1 ≤ d(g,f) ≤ 3}. Prove that B is a closed set

I'm new to all of this and just don't know what to do even with the f(x)=x²+2 part so if anyone out there can shed some light, I'd be really grateful!

Thanks
 
Physics news on Phys.org
You're trying to prove that sets are open and closed, not functions. I suggest you sketch the graph of f. Here, d(f,g) represents the maximum distance between two continuous functions f and g. So play around with the sketch, and then try to prove your observations.
 
morphism said:
You're trying to prove that sets are open and closed, not functions. I suggest you sketch the graph of f. Here, d(f,g) represents the maximum distance between two continuous functions f and g. So play around with the sketch, and then try to prove your observations.

Thank you for your advice, I'll try that and see how I get on

Thanks again
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K