MHB Proving Orthogonal Projection of Triangle V, v'_{1}

AI Thread Summary
The discussion focuses on proving the equation \( v_{1}=V \cos(\psi)+v'_{1} \cos(\theta - \psi) \) related to the orthogonal projections of triangle components. It is established that \( v_{1} \) represents the sum of the orthogonal projections of \( V \) and \( v'_{1} \) onto \( v_{1} \). Participants express difficulty in visualizing and calculating these projections. Clarification on the geometric interpretation and mathematical steps for deriving the projections is sought. Understanding these projections is crucial for validating the given expression.
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Given the triangle above where $$V < v'_{1}$$, prove that the \[ v_{1}=V \cos(\psi)+v'_{1} \cos(\theta - \psi) \]

It is said that $$v_{1}$$ is equal to the sum of the orthogonal projections on $$v_{1}$$ of $$V$$ and of $$v'_{1}$$ and that is precisely the expression that show. But I couldn't see how to make the projection and the calculations.
 
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