Proving Orthonormal Basis for an Orthogonal Matrix

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Homework Help Overview

The problem involves proving that if an n × n matrix A is orthogonal, meaning its column vectors are orthonormal, then these columns form an orthonormal basis for R^n with respect to the standard Euclidean inner product.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to demonstrate linear independence and spanning of R^n by the orthonormal vectors. There is mention of using basis coordinates and the implications of assuming the vectors already form a basis.

Discussion Status

Some participants have provided guidance on how to approach showing linear independence, suggesting the use of the dot product and properties of orthonormal vectors. There is an ongoing exploration of methods to prove the necessary properties without reaching a consensus on a specific approach.

Contextual Notes

Participants are navigating the constraints of proving linear independence and spanning without additional equations or assumptions beyond the orthonormality of the vectors.

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Homework Statement



Prove: if an n × n matrix A is orthogonal (column vectors are orthonormal), then the columns form an orthonormal basis for R^n.
(with respect to the standard Euclidean inner product [= the dot product]).

Homework Equations


None.


The Attempt at a Solution



I know that since the column vectors are orthonormal, all I have to show is that these vectors are also linearly independent and span R^n.

But I'm having some trouble showing this, so I was thinking about showing it through the basis coordinates:

u= <u, v1>v1 + <u, v2>v2 +...+ <u, vn>vn

But I think I have to start with assuming that the vectors v1, v2, ... vn form a basis. So I think that method can't work.
 
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Linear independence is what you want to show. That means c1*v1+c2*v2+...+cn*vn=0 (where vi are your orthonormal vectors and the ci are constants) only has the solution c1=c2=...=cn=0. Can you show that? Once you have that, any set of n linearly independent vectors in R^n is a basis.
 
I've been trying to figure out how, but I just can't seem to think of a way...anymore advice?
 
You assume c1*v1+c2*v2+...+cn*vn=0. What is vi.(c1*v1+...+cn*vn)? '.'=dot product. Use orthonormality.
 

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