Proving Positive Distance between Disjoint Compact Sets in R^n

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Homework Help Overview

The discussion revolves around proving that there exists a positive distance between two disjoint compact sets, X and Y, in R^n. The original poster attempts to establish this by considering the properties of compactness and the distance function.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of compactness on the distance function and question whether the minimum distance can be zero. There is uncertainty about the necessity of proving the compactness of the product set X x Y.

Discussion Status

Some participants have provided guidance on focusing on the minimum distance aspect rather than the compactness of the product set. There is an ongoing exploration of how to demonstrate that the minimum distance cannot be zero.

Contextual Notes

Participants express uncertainty about the proof structure and the assumptions made regarding the compactness of the product set. There is a lack of clarity on how to approach the proof effectively.

nicorette
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Homework Statement



X and Y are compact sets in R^n that are disjoint. Then there must be positive distance between the elements of these sets.


Homework Equations




The Attempt at a Solution



since X and Y are compact , X X Y is compact. Then, for the distance function d(x in X, y in Y): R^n X R^n -> R, there is a maximum and a minimum.

I think this should be a sufficient proof, although I'm not really sure how exactly to show that X X Y is compact as well.
 
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You've got the right idea, but you haven't shown the minimum can't be zero. Have you? Do you need to show XxY is compact? Or it that something you already proved?
 
I don't know how to show the minimum can't be zero. So far as X x Y being compact, I just assumed, I don't know where to start for a proof

thanks a lot
 
Don't worry about proving XxY compact for the moment, concentrate on the first one. Suppose the distance is zero. How can that be?
 

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