Proving Set Theory Basics: A \subseteq C

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SUMMARY

The discussion focuses on proving the transitive property of set theory, specifically that if \( A \subseteq B \) and \( B \subseteq C \), then \( A \subseteq C \). The proof provided uses direct logic based on the definitions of subsets and also suggests an alternative proof by contradiction. Both methods confirm the validity of the proof, demonstrating a clear understanding of set theory fundamentals.

PREREQUISITES
  • Understanding of set theory concepts, particularly subsets
  • Familiarity with logical reasoning and proof techniques
  • Knowledge of mathematical notation and symbols
  • Experience with proof by contradiction
NEXT STEPS
  • Study the properties of subsets in set theory
  • Learn about different proof techniques, including direct proof and proof by contradiction
  • Explore advanced topics in set theory, such as cardinality and set operations
  • Review examples of transitive properties in other mathematical contexts
USEFUL FOR

Students studying mathematics, particularly those focusing on set theory, logic, and proof techniques. This discussion is beneficial for anyone looking to strengthen their understanding of foundational mathematical concepts.

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Homework Statement



Trying to prove some of the basic laws in set theory, and would like any opinions on 1 of my proofs (eg hints on how can I improve it, is it even a valid proof). Thanks in advance.

(A \subseteq B \wedge B \subseteq C) \rightarrow (A \subseteq C)


Homework Equations





The Attempt at a Solution



1) \forall x \in A, x \in B$ - definition of a subset
2) \forall x \in B, x \in C - definition of a subset
3) \forall x \in A, x \in C - 1, 2
4) A \subseteq C - 3, definition of a subset
 
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Your logic is correct.

You could also use proof by contradiction:

Suppose A \nsubseteq C. Then there must be some a in A that is not in C. Since B \subseteq C, a cannot be in B. This contradicts A \subseteq B.
 
Last edited:

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