Proving Set Theory: Showing B is a Subset of S(n)

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Homework Help Overview

The problem involves set theory, specifically proving that a set B is a subset of some S(n) given certain conditions about the sets S(n) and their relationships with B. The context includes the use of the axiom of choice and considerations of infinite subsets.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the implications of the assumption that for every infinite subset B' of B, there exists some n such that B' intersect S(n) is infinite. There are suggestions to explore proof by contradiction and the construction of subsets from B. Questions arise regarding the case when B is finite and how to rigorously establish its relationship with S(n).

Discussion Status

Participants are actively exploring various approaches to the proof, including the potential use of Zorn's Lemma and the implications of finite versus infinite sets. Some guidance has been offered regarding the construction of subsets and the relationship between B and the union of S(n).

Contextual Notes

There is a mention of the axiom of choice and the specific nature of the sets S(n) being an increasing sequence. The discussion also touches on the conditions under which B is finite or infinite and the implications of these conditions on the proof.

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Homework Statement



Assume that S is a function with domain w such that S(n) is a subset of S(n^+) for each n in w. (Thus S is an increasing sequence of sets.) Assume that B is a subset of the union of S(n)'s for all n such that for every infinite subset B' of B there is some n for which B' intersect S(n) is infinite. Show that B is a subset of some S(n).

Elements of Set Theory, Enderton H.
Page 158 Question: 25

The Attempt at a Solution



I'm a little stuck on even starting this proof (not to mention from just thinking about it I can't seem to reason why it should be true).

I know I need to use the axiom of choice (Its in the axiom of choice chapter). I'm leaning toward a proof by contradiction though I don't know how to proceed. Any suggestions on how to start this proof would be greatly appreciated.
 
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Try this; I think it's a possible direction. Suppose the assumption (i.e. that for every infinite subset B' of B there is some n for which B' intersect S(n) is infinite) is true, but B is not a subset of any S(N). Then for any S(n), Ex (x is an element of B but x is not an element of S(n). Try constructing a subset B* of B as follows:

Let B*= {C(0), C(1)...} where:

C(0) is an element of B but not S(0).

Now look for the first S(n) such that C(0) is in S(n). Let C(1) be an element of B that is not in S(1). Show that (i) there will always be such a first S(n); (ii) there will always be such a C(1) and (iii) C(1) is not = C(0).

Repeat and look at the set of all C(n)s. Is it infinite? Does it satisfy the assumption?
 
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I'm trying to set up your proof, though it assumes that B is infinite. If B is finite how would I say with rigor that there must be some maximum S(n) therebye making B = S(n) for some n?

I think I have worked out the proof as you described. I'll work out the wording and post it when I get the chance.
 
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Remember that since B is a subset of U(S(n)), every element of B must be an element of some S(n). So if B is finite, it must be a subset of some finite union of S(n)s. And what do you know about a finite union of S(n)s where the sequence S(n) is increasing and infinite? (By the way, as the problem is stated, it's not necessary that B = S(n) for some n, and in general there's no reason I can see why it should be.)

There's probably a way to make this easier with Zorn's Lemma, but I'm too rusty/lazy to set it up.
 

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