Proving solutions to the schrodinger equation

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Homework Help Overview

The discussion revolves around verifying whether specific wave functions are solutions to the Schrödinger equation for a free particle. The wave functions in question are of the form \(\Psi(x,t) = A \cos(kx - \omega t)\) and \(\Psi(x,t) = A \sin(kx - \omega t)\).

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate derivatives of the wave functions and substitute them into the Schrödinger equation, leading to a relationship involving sine and cosine functions. They express uncertainty about their approach and seek guidance on simplifying their reasoning.
  • Another participant suggests that the derived relationship indicates that the wave function is not a solution, emphasizing the expectation that a valid solution should satisfy the equation for all values.
  • Further discussion includes a suggestion to express the cosine function in terms of complex exponentials to analyze the problem differently.

Discussion Status

Participants are actively engaging with the problem, exploring different methods and interpretations. Guidance has been offered regarding the implications of the derived relationships, and alternative approaches have been suggested, indicating a productive direction in the discussion.

Contextual Notes

Participants are navigating the complexities of the Schrödinger equation and its solutions, with some expressing confusion about the implications of their calculations. There is an acknowledgment of the need for clarity in understanding the conditions under which the wave functions can be considered valid solutions.

Bacat
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Homework Statement



Verify that the following are not solutions to the Schrödinger equation for a free particle:

(a) [tex]\Psi(x,t) = A*Cos(kx-\omega t)[/tex]

(b) [tex]\Psi(x,t) = A*Sin(kx-\omega t)[/tex]

Homework Equations



Schrödinger equation: [tex]\frac{-hbar^2}{2m}\frac{\partial^2\Psi}{\partial x^2} = \frac{i*hbar*\partial \Psi}{\partial t}[/tex]

The Attempt at a Solution



For part a:

Let [tex]y=kx-\omega t[/tex]

Calculating the derivatives gives...

[tex]\frac{\partial^2 \Psi}{\partial x^2}=-Ak^2*Cos y[/tex]
[tex]\frac{\partial \Psi}{\partial t} = A*\omega*Sin y[/tex]

Substituting and rearranging, we see that:

[tex]Sin y = \frac{hbar * k^2}{2mi\omega}Cos y[/tex]

Let [tex]f=\frac{hbar * k^2}{2mi\omega}[/tex]

Then [tex]Sin y = f Cos y[/tex]

The equality holds when [tex]y=\pm ArcCos(\pm\frac{1}{\sqrt{1+f^2}})[/tex]

If we substitute back in...

[tex]kx-\omega t = \pm ArcCos(\pm\frac{1}{\sqrt{1+\frac{hbar^2k^4}{4m^2\omega^2}}})[/tex]

If I assign some values to omega, m, hbar, and k, I can graph x as a function of t for one of the cases. It shows up as a straight line with a positive slope.

This does not seem to prove that (a) is not a solution to Schrödinger's equation. I think I may be making this more complicated than it is. How should I approach this problem differently?
 
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Bacat said:
[
Substituting and rearranging, we see that:

[tex]Sin y = \frac{hbar * k^2}{2mi\omega}Cos y[/tex]

Let [tex]f=\frac{hbar * k^2}{2mi\omega}[/tex]

Then [tex]Sin y = f Cos y[/tex]

This right here should tell you that [itex]\Psi(x,t) = A*Cos(kx-\omega t)[/itex] is not a solution to the Schrödinger equation. If it were, you would expect it to satisfy the Schrödinger equation everywhere (i.e. for all values of y)--- which it clearly doesn't.
 
a faster way would be to express cos(kx-[tex]\omega[/tex] t) in terms of ei(kx-[tex]\omega[/tex] t)
and substitute in the time dependent equation both will never satisfy it(coz the wavefunc. is of the form Aei(kx-[tex]\omega[/tex] t )
any ideas on this one mate..?
https://www.physicsforums.com/showthread.php?p=2218109#post2218109
 

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