Proving Stirling's Formula - Get Help Here

  • Context: Graduate 
  • Thread starter Thread starter mathstime
  • Start date Start date
  • Tags Tags
    Formula
Click For Summary
SUMMARY

The discussion focuses on proving Stirling's Formula, specifically the identity \(\binom{|\mathbbm{F}| + n -1}{n} = \frac{1}{n!} |\mathbbm{F}|^n + O(|\mathbbm{F}|^{n-1})\). Participants suggest starting with specific cases for small values of \(n\) (1, 2, and 3) to build understanding. The approach emphasizes the asymptotic behavior of binomial coefficients as \(u\) approaches infinity.

PREREQUISITES
  • Understanding of binomial coefficients
  • Familiarity with asymptotic notation (Big O notation)
  • Basic knowledge of limits and infinity in calculus
  • Experience with mathematical proofs
NEXT STEPS
  • Study the derivation of Stirling's approximation
  • Learn about asymptotic analysis in combinatorics
  • Explore proofs of binomial coefficient identities
  • Investigate the properties of limits involving factorials
USEFUL FOR

Mathematicians, students studying combinatorics, and anyone interested in understanding asymptotic analysis and binomial coefficients.

mathstime
Messages
25
Reaction score
0
Hi

I am looking to show that \binom{|\mathbbm{F}| + n -1}{n} = \frac{1}{n!} |\mathbbm{F}|^n + O(|\mathbbm{F}|^{n-1})

please could someone show me how??
 
Physics news on Phys.org
How about writing the problem: for each n,
<br /> \binom{u+n-1}{n} = \frac{u^n}{n!} + O(u^{n-1})<br /> \quad \text{as } u \to +\infty<br />

If that is what you mean, first try to prove it for n=1, n=2, n=3 and see
if you understand those.
 
got it! thanks!
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K