Proving that an alpha particle is a boson

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SUMMARY

The alpha particle, composed of two protons and two neutrons, can be shown to behave as a boson due to the symmetry of its total wave function. The total wave function for two identical particles is defined differently for bosons and fermions, with bosons exhibiting symmetric combinations and fermions exhibiting antisymmetric combinations. By analyzing the wave functions of the constituent protons and neutrons, it is established that the combination of two fermions (protons) and two fermions (neutrons) results in a symmetric wave function, confirming that the alpha particle is indeed a boson.

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  • Familiarity with the concepts of bosons and fermions
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1. Is there any way to prove that the alpha particle is a boson (its total wave function is symmetric), given that it's made up of two protons (fermions) and two neutrons (fermions)?

Homework Equations


The total wave function for two identical particles that are
(bosons) ψ_tot = 1/√2 * (ψ_a (particle 1) ψ_b (particle 2) + ψ_b (particle 1) ψ_a ( particle 2))
and
(fermions) ψ_tot = 1/√2 * (ψ_a (particle 1) ψ_b (particle 2) - ψ_b (particle 1) ψ_a ( particle 2)),
where "particle 1" and "particle 2" designate the coordinates of each particle, and
a,b designate states of each of the particles.

The Attempt at a Solution



For a single alpha particle,
ψ = P*N, where P is the wave function for the two protons and N is the wave function for two fermions.
P=1/√2 * (P_a(Proton 1)P_b(Proton 2) - P_b (Proton 1) P_a (Proton 2))
N= 1/√2 * (N_c(Neutron 1)N_d(Neutron 2) - N_d (Neutron 1) N_c(Neutron 2)),
where a,b describe the states for each of the two protons
and c,d does the same for each of the two neutrons.

For a pair of alpha particles,
ψ_tot = 1/√2 * (ψ_{abcd} (Alpha particle 1) * ψ_{efgh} (Alpha particle 2) \pm ψ_{efgh} (Alpha particle 1) * ψ_{abcd} (Alpha particle 2)},
and our goal is to know whether we should use the plus sign (if the alpha particle is a boson) or the minus sign (if the alpha particle is a fermion).At this point I'm stuck. How can we find out which sign to use? I appreciate any help!
 
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Do it step by step. Show that combining two fermions you get a boson and combining two bosons you get another boson and combining a boson with a fermion produces a fermion. Than show by iteration that the combination of multiple particles will be a fermion if and only if (iff for mathematicians) it contains an odd number of fermions inside. Finally count the total number of fermions inside an alpha particle to figure out whether or not it is a fermion.
 
So take two fermions. Together, they can form a particle described by the wave function, ψ:
ψ=2^{-0.5}*(ψ_{a}(1)ψ_{b}(2)-ψ_{b}(1)ψ_{a}(2))..
What I need to do is show that this composite particle of two fermions is a boson.

I see how this is a simplified version of my original problem, but I don't see how I can use this new wave function to show that the composite particle is a boson.
 

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