Proving that the product rule for differentiating products applies to vectors

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SUMMARY

The product rule for differentiating the dot product of two vectors, r and s, is established as follows: d/dt (r·s) = r·(ds/dt) + (dr/dt)·s. This formula applies when both r and s are time-dependent vectors. The proof begins with the expansion of the dot product into its component form, specifically r_x s_x + r_y s_y + r_z s_z, and differentiating each term with respect to time.

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  • Understanding of vector calculus
  • Familiarity with the dot product of vectors
  • Knowledge of differentiation rules
  • Basic concepts of time-dependent functions
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  • Study the properties of the dot product in vector calculus
  • Learn about differentiation of vector functions
  • Explore applications of the product rule in physics
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a.merchant
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If r and s are vectors that depend on time, prove that the product rule for differentiating products applies to r.s, that is that:

d/dt (r.s) = r. ds/dt + dr/dt .s


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I'm not entirely sure how I'm supposed to go about proving this, can anyone point me in the right direction, please?

Homework Statement

 
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[tex]\frac{d}{dt} (\vec{r}\cdot\vec{s}) = \frac{d}{dt}(r_x s_x + r_y s_y + r_z s_z)[/tex]
 

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