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Proving that the sum of (u^x)/x! from 0 to infinity = e^u

  1. Apr 21, 2013 #1
  2. jcsd
  3. Apr 21, 2013 #2

    tiny-tim

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    Hi CraigH! :smile:

    Isn't that the definition of eu ?

    (and you can check it by working out euev, or by differentiating it :wink:)
     
  4. Apr 21, 2013 #3

    dextercioby

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    Do you know about the MacLaurin series expansion ? What is it for ex ?
     
  5. Apr 21, 2013 #4
    Ah yes, I've just looked up the MacLaurin series for e^x in my data book, its give me the answer i was hoping for. I needed to know as part of a proof for a different equation.

    So in my exam just saying:

    "From the MacLaurin series:
    The sum of (u^x)/x! from 0 to infinity = e^u"

    Should be enough then.

    Thank you for answering.
     
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