Proving the Closedness of a Linear Subspace in a Normed Space Using Dual Spaces

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SUMMARY

The discussion focuses on proving the closedness of a linear subspace S in a normed space X, where S is defined as the span of a closed linear subspace F and an element z not in F. The function f: S → Φ is defined by f(x + az) = a, demonstrating that |f| ≤ 1/d, where d is the distance from z to F. A sequence {x_n + a_n z} converging to w is analyzed, with the goal of showing that w belongs to S. The discussion emphasizes the need to establish the convergence of both x_n and a_n z separately.

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Let X be a normed space, F be a closed linear subspace of X,
Let z be in X, z is not in F.
Let S={x+az:a is in the field Phi}=Span of F and z
We show S is closed.

I would define a function f : S--> Phi by f(x+az)=a
and show that |f|< or equal to 1/d where d= distance(z,F)
hence f is in S* (dual of S).
So we let {x_n +a_n z} be a sequence converging to w (x_n is in F,a_n is in Phi). We show w is in S.
We note {f(x_n +a_n z)} is a cauchy sequence.

But I am not sure how to proceed.
 
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You might also note that for x_n in F, d(x_n+a_n*z,F)=d(a_n*z,F). You want to show x_n and a_n*z are both convergent separately.
 

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