Proving the Existence of an Interval in a Lebesgue Measure Space

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SUMMARY

The discussion focuses on proving that in a Lebesgue measure space (R, M, m), if a set E has positive measure (m(E) > 0), then the set E - E, defined as {x in R | exists a, b in E with x = a - b}, contains an interval centered at the origin. The proof strategy involves contradiction and utilizes the property that for every a in (0,1), there exists an interval I such that m(E ∩ I) > a * m(I). This establishes the existence of an interval within the set E - E.

PREREQUISITES
  • Understanding of Lebesgue measure theory
  • Familiarity with set operations in real analysis
  • Knowledge of measure properties and intervals
  • Proficiency in proof techniques, particularly proof by contradiction
NEXT STEPS
  • Study the properties of Lebesgue measure spaces
  • Learn about the concept of set differences and their implications in measure theory
  • Explore the implications of the Vitali covering theorem
  • Investigate the relationship between measure and integration in Lebesgue spaces
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Mathematicians, students of real analysis, and anyone studying measure theory who seeks to understand the properties of Lebesgue measure spaces and their applications in proving set existence.

Funky1981
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Homework Statement


Let (R,M,m) be Lebesgue measure space in R. Given E contained in R with m(E)>0 show that the set
E-E defined by

E-E:={x in R s.t. exists a, b in E with x= a-b }

contains an interval centered at the origin

Homework Equations



try to prove by contradiction and use the fact that for every a in (0,1) there exists an interval I s.t. m(E∩ I)>am(I)
 
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