Proving the Inequality: x^4+x^3y+x^2y^2+xy^3+y^4 > 0 for x,y>0

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Homework Help Overview

The discussion revolves around proving the inequality \(x^4+x^3y+x^2y^2+xy^3+y^4 > 0\) for positive values of \(x\) and \(y\). Participants are exploring various approaches to establish this inequality, with a focus on algebraic manipulation and factorization.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss factoring the expression and simplifying it by substituting \(t = \frac{y}{x}\). There are hints about recognizing sequences and using polynomial identities. Some participants express confusion about how to proceed after initial manipulations.

Discussion Status

The conversation is ongoing, with various hints and suggestions being offered. Some participants have made progress in their understanding, while others are still seeking clarity on specific points. There is acknowledgment of special cases, particularly when \(x\) and \(y\) are equal.

Contextual Notes

Participants note that both \(x\) and \(y\) must be greater than zero, and there is discussion about the implications of \(x\) and \(y\) being equal, which raises questions about the validity of certain simplifications.

silina01
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Prove that if x and y are not both , then x^4+x^3y+x^2y^2+xy^3+y^4 > 0

I have no idea how to start this proof, can anyone give me an idea?
 
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Here's a hint for one way to do it. If x=0 it's clearly true. If x is not zero, then factor x^4 out and look at the other factor. Remind you of anything?
 
sorry I meant to say that if x and y are both not 0
 
Hint: This expression can be simplified.
 
I factored out x^4 and got x^4 [(y/x)^4 + (y/x)^3 +(y/x)^2 + y/x +1] I see that all these terms have y/x so if i let t = y/x then it'll be x^4 [t^4 + t^3 +t^2 + t +1] (just so it is easier to visualize) but I am stuck, How do i simplify it further?
 
Hint: think about a certain sequence.
 
I am still lost
 
What special sequences do you know of?
 
x^n - y^n = (x - y) (x^n-1 + x^n-2y+ ...+ xy^n-2 + y^n-1 )??
 
  • #10
silina01 said:
x^n - y^n = (x - y) (x^n-1 + x^n-2y+ ...+ xy^n-2 + y^n-1 )??
That'll do it. So how can you use that to rewrite the original expression?
 
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  • #11
haruspex said:
That'll do it. So how can you use that to rewrite the original expression?

(x^5 - y^5)/(x - y) = x^4 + x^3y + x^2y^2 + xy^3 + y^4 , is that correct?
 
  • #12
ahhhh I see it know, in both cases if x-y <0 or if x-y>0 the quotient will always be positive. Thanks everyone.
 
  • #13
silina01 said:
ahhhh I see it know, in both cases if x-y <0 or if x-y>0 the quotient will always be positive. Thanks everyone.
Right, but there is one special case you need to address separately.
 
  • #14
what would that be?
 
  • #15
x and y cannot be 0 by the way
 
  • #16
silina01 said:
what would that be?
Your expression involves 1/(x-y). What doubt should that create?
 
  • #17
silina01 said:
x and y cannot be 0 by the way

But they can be nonzero and equal.
 
  • #18
Dick said:
But they can be nonzero and equal.

But if you simplify the fraction then there is no problem.
 
  • #19
dirk_mec1 said:
But if you simplify the fraction then there is no problem.

I didn't say there was a problem, but x=y is a special case.
 
  • #20
Assume that x,y&gt;0.Let P(x,y)be the polynomial, then P(x,y)=P(-x,-y)\ge P(x,-y)=x^4+y^4-x^3y-xy^3+x^2y^2\ge x^2y^2\ge 0 And the equality cannot hold.
 
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