Proving the Least Upper Bound Property: A Mathematical Inquiry

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SUMMARY

The discussion centers on proving the Least Upper Bound (LUB) property for a nonempty set A with an upper bound x. It establishes that x is the least upper bound if, for any ε > 0, there exists a y in A such that y > x - ε. The participants explore the implications of assuming x is an upper bound and the necessity of demonstrating that no number z < x can serve as an upper bound for A. The proof requires careful consideration of the relationship between y and z to confirm y's status as the least upper bound.

PREREQUISITES
  • Understanding of the Least Upper Bound property in real analysis
  • Familiarity with epsilon-delta definitions in mathematical proofs
  • Basic knowledge of upper and lower bounds in set theory
  • Experience with constructing mathematical proofs
NEXT STEPS
  • Study the formal definition of the Least Upper Bound property in real analysis
  • Learn about epsilon-delta proofs and their applications in mathematical analysis
  • Explore examples of sets and their upper bounds to solidify understanding
  • Practice constructing proofs involving upper and lower bounds in various mathematical contexts
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Mathematics students, educators, and anyone interested in real analysis or proof construction will benefit from this discussion.

ssayan3
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Least Upper Bound proof...

Homework Statement


Suppose A is a nonempty set that has x as an upper bound. Prove that x is the least upper bound of the set A iff for any E>0 there exists a y in A such that y>x-E


Homework Equations


None


The Attempt at a Solution


The forward where you assume that x is the least upper bound is very easy, but I'm having some trouble proving the reverse...

This is what I have so far...

Let x be an upper bound of A, and choose a point z in A.
If x is an upper bound of A, then x+z is also an upper bound.
 
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To prove the reverse, you are given that x is an upper bound for A having the property:

If \epsilon &gt; 0 there is a y in A satisfying x - \epsilon < y

You have to show that no number z < y is an upper bound for A. What problem would arise if there was such a number z?

[Edit] Sorry, there is a typo. The last paragraph should have read:

You have to show that no number z < x is an upper bound for A. What problem would arise if there was such a number z?
 
Last edited:


Hmm... if there were such a number z, then y could not be the least upper bound...

Could the proof go something like this?:

Choose arbitrary E>0, and let y be an upper bound of A

Suppose z is an upper bound of A, and y>z>y-E.

y is not the lub

does this finish the proof?
 


ssayan3 said:
Hmm... if there were such a number z, then y could not be the least upper bound...

Could the proof go something like this?:

Choose arbitrary E>0, and let y be an upper bound of A

Suppose z is an upper bound of A, and y>z>y-E.

y is not the lub

does this finish the proof?

No. Sorry, but I had a typo which I have corrected. Read my reply and try again.
 

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