Proving the Relation in "Methods of Theoretical Physics

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The discussion centers on proving the relationship that indicates displacement is perpendicular to a surface as described in "Methods of Theoretical Physics" by Morse and Feshbach. The key equation presented is that the components of displacement (dx, dy, dz) satisfy the condition where their ratio equals the partial derivatives of a function ψ. A participant suggests that this can be expressed as the dot product of the displacement vector with the gradient of ψ equating to zero. This implies that the displacement vector is orthogonal to the gradient, confirming the perpendicularity condition. The conversation emphasizes understanding the mathematical foundation behind this physical concept.
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Homework Statement


In "Methods of theoretical physics" from the authors Morse and Feshbach is writen:
" The displacement (dx,dy,dz) is perpendicular to the surface if the component displacemetn satisfy the equation:



How to prove this relation?



Homework Equations


the relevant equation is the equation of total change



The Attempt at a Solution

 
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hi arbri! welcome to pf! :smile:
arbri said:
In "Methods of theoretical physics" from the authors Morse and Feshbach is writen:
" The displacement (dx,dy,dz) is perpendicular to the surface if the component displacemetn satisfy the equation:

$$\frac{dx}{\partial \psi /\partial x} = \frac{dy}{\partial \psi /\partial y} = \frac{dz}{\partial \psi /\partial z}$$

How to prove this relation?

that's just (dx,dy,dx)·∇ψ = 0 :wink:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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