Proving trig identities with dot and cross products

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SUMMARY

This discussion focuses on proving trigonometric identities using dot and cross products of vectors in the xy-plane. Specifically, it establishes the identities cos(α-β) = cos(α)cos(β) + sin(α)sin(β) and sin(α-β) = sin(α)cos(β) - cos(α)sin(β) by evaluating the dot product a • b in two ways: a • b = abcos(θ) and a • b = a1b1 + a2b2. Additionally, it explores the components of vectors a and b, defined as ax = a*cos(α), ay = a*sin(α), bx = b*cos(β), and by = b*sin(β), to facilitate these proofs.

PREREQUISITES
  • Understanding of vector operations, specifically dot and cross products.
  • Familiarity with trigonometric identities and their applications.
  • Knowledge of vector components in the xy-plane.
  • Basic proficiency in algebra and geometry.
NEXT STEPS
  • Study vector component breakdown in two dimensions.
  • Learn about the geometric interpretation of dot and cross products.
  • Explore additional trigonometric identities and their proofs.
  • Investigate applications of vector operations in physics and engineering.
USEFUL FOR

Students studying physics or mathematics, educators teaching vector calculus, and anyone interested in understanding the relationship between trigonometry and vector operations.

cytochrome
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Homework Statement



The two vectors a and b lie in the xy plane and make angles α and β with the x axis.

a)By evaluating ab in two ways (Namely ab = abcos(θ) and ab = a1b1+a2b2) prove the well-known trig identity
cos(α-β)=cos(α)cos(β)+sin(α)sin(β)

b)By similarly evaluating a X b prove that
sin(α-β) = sin(α)cos(β) - cos(α)sin(β)

c)Now let vector a make an angle -α with the x axis and find a similar expression for
cos(α+β)


Homework Equations



ab = abcos(θ)

ab = a1b1+a2b2



The Attempt at a Solution



I drew the vectors a and b with their appropriate angles to the x-axis... The angle between the vectors is (α-β) so I have ab = abcos(α-β) but I have no idea how to relate this to the trig identities!
 
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cytochrome said:

Homework Statement



The two vectors a and b lie in the xy plane and make angles α and β with the x axis.

a)By evaluating ab in two ways (Namely ab = abcos(θ) and ab = a1b1+a2b2) prove the well-known trig identity
cos(α-β)=cos(α)cos(β)+sin(α)sin(β)

b)By similarly evaluating a X b prove that
sin(α-β) = sin(α)cos(β) - cos(α)sin(β)

c)Now let vector a make an angle -α with the x axis and find a similar expression for
cos(α+β)

Homework Equations



ab = abcos(θ)

ab = a1b1+a2b2

The Attempt at a Solution



I drew the vectors a and b with their appropriate angles to the x-axis... The angle between the vectors is (α-β) so I have ab = abcos(α-β) but I have no idea how to relate this to the trig identities!
What are the components of vector, a, in terms of a (the magnitude of the vector) and the angle α?

What are the components of vector, b, in terms of b (the magnitude of the vector) and the angle β?
 
SammyS said:
What are the components of vector, a, in terms of a (the magnitude of the vector) and the angle α?

What are the components of vector, b, in terms of b (the magnitude of the vector) and the angle β?

The components of a are ax*cos(α) and ay*sin(α)

The components of b are bx*cos(β) and by*sin(β)

Thanks for reminding me about that I'll see where I can get from here
 
cytochrome said:
The components of a are ax*cos(α) and ay*sin(α)

The components of b are bx*cos(β) and by*sin(β)

Thanks for reminding me about that I'll see where I can get from here

Not quite right.

The components of a are ax = a*cos(α) and ay = a*sin(α)

etc.

B.T.W. ax = a1, etc. in your Relevant equations for the dot & cross products.
 
What are a1, a2, b1, and b2 in terms of a, b, α, and β?
 
vela said:
What are a1, a2, b1, and b2 in terms of a, b, α, and β?

a1 = acos(α)
a2 = asin(α)

b1 = bcos(β)
b2 = bsin(β)

a dot b = acos(α)bcos(β) + asin(α)bsin(β)

which pretty much completes the proof for a)
 
cytochrome said:
a1 = acos(α)
a2 = asin(α)

b1 = bcos(β)
b2 = bsin(β)

a dot b = acos(α)bcos(β) + asin(α)bsin(β)

which pretty much completes the proof for a)
Do something similar for (b).

( a × b )3 = a1*b2 - a2*b1 . If both vectors are in the xy-plane, then the other components are zero.
 

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