Pulley & Tension: Solving for Acceleration and Tension

  • Thread starter Thread starter whitehorsey
  • Start date Start date
  • Tags Tags
    Pulley Tension
Click For Summary
SUMMARY

The discussion focuses on solving for acceleration and tension in a pulley system involving a block on an inclined plane and a hanging mass. The equations derived include F = ma, with specific calculations yielding an acceleration of 1.225 m/s² and a tension of 22.05 N. Key concepts include the use of free-body diagrams (FBDs) to visualize forces, the importance of defining positive and negative directions, and the algebraic approach to solving the equations before substituting numerical values.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of free-body diagrams (FBDs)
  • Familiarity with trigonometric functions, specifically sin(30°)
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the application of free-body diagrams in complex systems
  • Learn about the effects of friction on inclined planes
  • Explore the concept of negative acceleration in physics
  • Practice solving pulley problems with varying masses and angles
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for effective teaching strategies in problem-solving and visualization techniques.

whitehorsey
Messages
188
Reaction score
0
1. See Attachment
question.JPG


2. F = ma


3. For the block on the incline plane, I know it has Fnormal, Fweight, and Ftension. While the one hanging has Ftension and Fweight.

Fn = 6gcos30
ƩFx = 6gcos30 - T = 6a
6gsin30 - (2g +2a) = 6a
6gsin30 -2g = 8a
2g(3sin30 - 1) = 8a
a = 1.225

T = 6gsin30 - 6a
= 22.05N

Is this correct? And when do I use negative acceleration versus positive acceleration?
 
Physics news on Phys.org
As a matter of policy, I don't like telling people whether a specific answer is correct or not.
At some stage you will have to deal with problems where nobody knows the answer and you need to get used to this. Besides, I can make mistakes as easily as you - why should you trust my answer any more than your own?
Instead I'll try to show you how to have confidence in your results.

One of the ways to have confidence in your working is to draw th pictures - in this case, two free body diagrams. Did you do this? It's OK that you didn't post them - but you should do them. The fbds should give you three equations that are coupled together - but you are only interested in two of them. Is your working consistent with the free-body diagrams? i.e. you have written that Fx=Fn-T = Ma (using M for the big mass and m is the little mass - cute eh? Note: it is best to do the algebra first) - does this make sense from your fbd for M?

Another way is to comment your working as you go - in words.
eg. what are you defining as the "x" component? which way is "positive"? you need to be clear on this point.

Related to this is doing the algebra first, avoid subscripts, encode directions explicitly with the + or - sign, and put the numbers in only at the end. This makes it easier to troubleshoot your working.

In your equations, you want the letters to represent magnitudes and put the + or - sign in for direction.
If the magnitude turns out to be negative, when you done the math, then it just means the direction should have been opposite.

To your question: a negative acceleration is a slowing-down in the positive direction and a speeding-up in the negative direction. This is why it is important to define your directions on the fbd. All you need to know is the direction of the net force on either mass.

BTW: 30deg is a very nice angle - sin(30)=0.5
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 6 ·
Replies
6
Views
9K