Pulley Motion Analysis: Determining Tension in a String

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem related to pulley motion and the determination of tension in a string, specifically focusing on the variables involved, such as mass (m) and gravitational acceleration (g).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster seeks to clarify the interpretation of the problem, particularly the meaning of expressing tension in terms of m and g. Some participants discuss whether m and g are to be treated as known values or left as variables in the expression for tension.

Discussion Status

The conversation is ongoing, with participants providing clarification on the interpretation of the question. There is a shared understanding that m and g should remain as variables in the expression for tension, and the original poster expresses relief at this clarification.

Contextual Notes

There is an indication that the original poster plans to provide the full question later, suggesting that further details may influence the discussion.

_Mayday_
Messages
808
Reaction score
0
Hey, I will post the actual question later. First of all I would like to just make sure I have interpreted the question correctly.

The Question

(a) By considering the motion of A, find, in terms of m and g, the tension in the string.

What is it actually asking me here? In terms of, does that mean find a value for m and g or what?

Thank you
_Mayday_
 
Physics news on Phys.org
It is looking for the tension. m and g, will appear as variables, in the expression for Tension.
 
I'm sorry I don't understand that. Does that mean that m and g could be unknown?
 
_Mayday_ said:
I'm sorry I don't understand that. Does that mean that m and g could be unknown?

Yes, it just means leave m and g in as terms in the tension; you don't need to bother working out what they are.
 
That is great news! That means I haven't gone wrong yet. I'll post the question here in a bit if I get stuck. Thanks to you both! :smile:
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 15 ·
Replies
15
Views
7K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
Replies
15
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K