Pushing a Box On A Plane 30deg Plane Help?

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Homework Statement



Image2.jpg


Homework Equations



F=MA

The Attempt at a Solution



Weight
M*G=55.5*9.81

Parallel force
sin(30)544.455=272.228

Perpendicular force To Plane
cos(30)544.455=471.512

Figured out that the man is pushing with a force of
tan(30)544.455=314.341N

Normal Force
Wouldn't it be the opposite to the perpendicular force? 471.512? But this is wrong? HELP. What other force in the perpendicular direction am I missing?
 
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raven2783 said:

Homework Statement



Homework Equations



F=MA

The Attempt at a Solution



Weight
M*G=55.5*9.81

Parallel force
sin(30)544.455=272.228

Perpendicular force To Plane
cos(30)544.455=471.512

Figured out that the man is pushing with a force of
tan(30)544.455=314.341N

Normal Force
Wouldn't it be the opposite to the perpendicular force? 471.512? But this is wrong? HELP. What other force in the perpendicular direction am I missing?

OK you have the weight of the box perpendicular and parallel ok.

Now the man is pushing with a force that has 2 components too. Since it is at rest, you correctly balanced the downward plane force of the box with the upward plane force from the man and part b) looks correct.

For the last one there are two normal forces to the ramp. The gravity related component added to the Sin30 component of the man pushing .