1. The problem statement, all variables and given/known data A force F pushes two boxes, box 1 and box 2 up an inclined plane of 30 degrees. If F=25 N and box 1 is 2 kg and box 2 is 3 kg, what is the force exerted on the 2 kg box by the 3 kg box. Assume no friction. 2. Relevant equations F=ma. 3. The attempt at a solution Since the boxes' accelerations are the same, I decided to resolve the 2 kg box's weight into mgsin(theta) and mgcos(theta). Since mgcos(theta) is equal and opposite to the normal force on the 2 kg box, I thought that the magnitude of the force with which the 3 kg box exerts on the 2 kg box equals mgsin(theta) for the 2 kg box. So the answer to the problem I thought would be mgsin(theta) which would be (2 kg)(9.8 m/s^2)(30 degrees) which is 9.8 N.