Q: Would you rather land on water or marshmallow?

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SUMMARY

The forum discussion centers on the hypothetical scenario of landing on water versus marshmallow without a parachute. Participants, including Matt, an experienced skydiver with over 65 jumps, conclude that marshmallow is a safer landing option due to its compressibility compared to the incompressibility of water, which poses a greater risk of injury upon impact. Key factors discussed include terminal velocity, surface tension, and the compressibility of marshmallow, leading to calculations suggesting that a depth of approximately 150 meters of marshmallow may be required to safely cushion a fall from 30,000 feet.

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  • Understanding of terminal velocity in freefall scenarios.
  • Knowledge of compressibility and density concepts.
  • Familiarity with basic physics equations related to kinetic energy and force.
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  • Research the physics of terminal velocity and its implications for skydiving.
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This discussion is beneficial for physics enthusiasts, skydivers, and anyone interested in the practical applications of material science and impact dynamics.

  • #31


tiny-tim said:
But is marshmallow springy …

does it return to its original shape?

If not, then "spring constant" isn't the issue.

A spring absorbs energy, and then returns it …

a "crumple zone" absorbs energy, but keeps it …

I thought that was why MattSimmons :smile: chose marshmallow in the first place?
That is why I assumed a constant rupture force rather than a spring model.
 
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  • #32
i can stop by the local Tractor Supply store and pick up some 1/2 inch washers..these are about the size of a half dollar. if i stack these , one a t a time, we should see when the marshmellow collapses ..this the stree ruoture rate you were talking about?
any other advise on method to use?
freeze um first?
do i need my infrared pyrometer too?
 
  • #33


tiny-tim said:
But is marshmallow springy …

does it return to its original shape?

If not, then "spring constant" isn't the issue.

A spring absorbs energy, and then returns it …

a "crumple zone" absorbs energy, but keeps it …

I thought that was why MattSimmons :smile: chose marshmallow in the first place?

So it would be a landing zone that doubles as a trampoline! Sounds fun! :P
 
  • #34
rupture force

Hi DaleSpam! :smile:
DaleSpam said:
That is why I assumed a constant rupture force rather than a spring model.

ah, i missed that … you posted it just before my last post

but what is rupture force (it doesn't sound very nice :frown:)?

i wiki'ed it, but couldn't find anything. :redface:
DyslexicHobo said:
So it would be a landing zone that doubles as a trampoline! Sounds fun! :P

hmm … that's what was bothering me :redface:

falling 20,000 feet onto a trampoline doesn't seem much better than crashing! :biggrin:

:rolleyes: boinggg! boinggg! :rolleyes:
 
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  • #35


tiny-tim said:
but what is rupture force (it doesn't sound very nice :frown:)?
It is point number 3 on this http://en.wikipedia.org/wiki/Stress-strain_curve" (Figure 1). Basically, it is the point where the material breaks, complete failure.

So, to measure it you would push on a marshmallow until it failed and measure the force and the area that you were pushing.
 
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  • #36
rupture force and viscosity

DaleSpam said:
It is point number 3 on this http://en.wikipedia.org/wiki/Stress-strain_curve" (Figure 1). Basically, it is the point where the material breaks, complete failure.

So, to measure it you would push on a marshmallow until it failed and measure the force and the area that you were pushing.

ah … got it! :biggrin:

so below the rupture force, the marshmallow will act to some extent like a spring, returning MattSimmons upward with a fairly high overall deceleration,

but beyond the rupture force, the marshmallow will continuously give way, providing a relatively safe steady viscous deceleration? :smile:

hmm … so now we also need to know the viscosity of marshmallow? :confused:

and presumably it would help to be covered with chocolate, or with some other material that will reduce marshmallow drag? :wink:
 
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  • #37
those marshmallows are tuffer than I thought. got a bag of Wal-Mart Great Value Marshmallows..these are the biggies..weigh 6 grams, 3 mm tall 30.2 mm diameter
did the measurements when they were 64 degrees..were in trunk over night
I stacked various washers on top until one side of the marshmallow wall gave in..I was not yet able to load the marshmallow to blow it out.total collapse.
in fact , I was only able to load 540 gram max load and the darn thing still did not fail to return to 3 mm height after load. I have to find some bar stock of sufficient weight to mash it
the height is from edge of a dished washer to the desk top and measured with a pocket scale ..note i used the slider bar on the pocket scale


the following was with washers perfectly balance

load - height mm
0 - 3.0
50 - 2.8
85 - 2.4
102 - 2.2
150 - 2.1
215 - tilt, side wall failure


I has to steady the washers by holding them so side wall would not collapse

load - height in mm
0 - 2.2
140 - 2.0
210 - 1.8
280 - 1.7
540 - 1.3
824 - 1.2
 
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  • #38
Ranger Mike said:
those marshmallows are tuffer than I thought. got a bag of Wal-Mart Great Value Marshmallows..these are the biggies..weigh 6 grams, 3 mm tall 30.2 mm diameter
did the measurements when they were 64 degrees..were in trunk over night
I stacked various washers on top until one side of the marshmallow wall gave in..I was not yet able to load the marshmallow to blow it out.total collapse.
in fact , I was only able to load 540 gram max load and the darn thing still did not fail to return to 3 mm height after load. I have to find some bar stock of sufficient weight to mash it
the height is from edge of a dished washer to the desk top and measured with a pocket scale ..note i used the slider bar on the pocket scale


the following was with washers perfectly balance

load - height mm
0 - 3.0
50 - 2.8
85 - 2.4
102 - 2.2
150 - 2.1
215 - tilt, side wall failure


I has to steady the washers by holding them so side wall would not collapse

load - height in mm
0 - 2.2
140 - 2.0
210 - 1.8
280 - 1.7
540 - 1.3
824 - 1.2
How big are the marshmallows? 1" in diameter by 1" tall? If so, using 215 g/in² (most marshmallows will probably fail this way rather than rupture), and a surface area of .7 m² (good for 74 kg adult male, so a little conservative for a 100 kg man) we get a revised force of 2300 N which is a little more than double my previous guesstimate. So 180 kJ/2300 N = ~ 80 m. Multiply by a factor of 2.5 for safety and call it 200 m of marshmallows.
 
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