ehrenfest
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Homework Statement
Zwiebach QC 5.2
Tau is the parametrization of a worldline. p is the relativistic momentum
Show that [tex]\frac{ dp_{\mu}}{d \tau'}} = 0[/tex]implies that [tex]\frac{ dp_{\mu}}{d \tau'}} = 0[/tex] holds for an arbitrary paramter [tex]\tau'(\tau))[/tex]
What needs to be true about the derivative of tau' with respect to tau for tay' to be a good parameter when tau is a good one?
Homework Equations
The Attempt at a Solution
By the chain rule dp/dtau *dtau'/dtau = dp/dtau * dtau/dtau' but we only have tau' as a function of tau and I am not sure whether you can just flip the differentials in that derivative?