QM Free Particle Approaching Infinite Barrier

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SUMMARY

The discussion centers on the solution to a quantum mechanics problem involving a free particle approaching an infinite barrier, specifically using the time-independent Schrödinger Equation. The wavefunction for the particle is expressed as Psi(x) = B sin(kx), derived from the general solution Psi(x, 0) = A e^(ikx) + B e^(-ikx). The reflection coefficient is determined to be 1, indicating total reflection at the barrier. The participant clarifies the continuity condition at x = 0, leading to the conclusion that A = -B.

PREREQUISITES
  • Understanding of the time-independent Schrödinger Equation
  • Familiarity with wavefunctions and boundary conditions in quantum mechanics
  • Knowledge of reflection coefficients in quantum systems
  • Basic concepts of energy conservation in quantum mechanics
NEXT STEPS
  • Study the implications of boundary conditions on wavefunctions in quantum mechanics
  • Learn about the derivation and interpretation of reflection coefficients in quantum systems
  • Explore the concept of allowed energy states in quantum mechanics
  • Investigate the role of the infinite potential barrier in quantum mechanics
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Students and professionals in quantum mechanics, particularly those studying wave-particle interactions and barrier problems. This discussion is beneficial for anyone looking to deepen their understanding of wavefunctions and reflection phenomena in quantum systems.

leothelion
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Solved... i think. It's just Psi(x) = B sin kx

Homework Statement


Consider a free particle psi(x) = A*e^(ikx) approaching an infinite barrier from the left:
V = 0, x < 0 and V = oo, x >= 0. For this problem use only the time-independent
Schrödinger Equation.
a. Find the probability of being reflected from the barrier (recall that energy
must be conserved).
b. Find the total wavefunction Psi(x) for x < 0.

Homework Equations



Schroedinger's equation.

The Attempt at a Solution



Okay, solving the wave equation gives the general solution

psi(x, 0) = A e^(ikx) + B e^(-ikx).

We know that Psi(x, 0) = 0 when x >= 0, since E < V = oo for all values of E. Part a asks to find the reflection coefficient using conservation of energy, but I did it this way:

Psi must be continuous at x = 0. Thus A + B = 0, implying that A = -B. Thus the reflection coefficient is 1. This also reduces psi(x, 0) = A sin kx.

However, I'm a little confused as to how to find Psi(x). My original work was that Psi(x) = integral(-oo to oo) phi(k) A sin kx dk

but my professor said that due to the conservation of energy, there are only so many allowed energy states. I'm a little confused about this. Is Psi(x, 0) = A e^(ikx) - A e^(-ikx)?

Any hints would be greatly appreciated. Thanks!
 
Last edited:
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leothelion said:
Solved... i think. It's just Psi(x) = B sin kx
Yep, that's it!
 

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