Quadratic Equation: Finding Values of 'a' Between 2 and 4 with Only One Root

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The discussion centers on finding values of 'a' for the quadratic equation x² - 2ax + a² - 1 = 0, ensuring exactly one root lies between 2 and 4, without being equal to either. Initial attempts led to the conclusion that 'a' could be in the interval (1, 3), but the correct answer is (1, 5) - {3}. Participants emphasize that using the quadratic formula simplifies the problem, eliminating the need for graphical representation. They highlight the importance of solving multiple inequalities to arrive at the final solution. The conversation concludes with a collaborative understanding of the problem-solving process.
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Homework Statement


Find all the values of 'a', so that exactly one root of the equation x2-2ax+a2-1=0, lies between the numbers 2 and 4, and no root is either equal to 2 or equal to 4.

Homework Equations


The Attempt at a Solution


Let f(x)=x2-2ax+a2-1
I tried to visualize the question by graph. The graph could have been like this (this is only a rough sketch):-
2qci6hi.jpg

From here, i get three inequalities,
f(2)<0 and f(4)>0 and D>0
Solving these inequalities, i get a can lie in interval (1,3).
But this is not the answer, the answer is (1,5)-{3}.
Then i thought that graph could be also like this:-
kb20d4.jpg

But this gives completely different set of inequalities, now i am completely stuck.

Any help is appreciated. :)
 
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Pranav-Arora said:

Homework Statement


Find all the values of 'a', so that exactly one root of the equation x2-2ax+a2-1=0, lies between the numbers 2 and 4, and no root is either equal to 2 or equal to 4.

Homework Equations


The Attempt at a Solution


Let f(x)=x2-2ax+a2-1
I tried to visualize the question by graph. The graph could have been like this (this is only a rough sketch):-
2qci6hi.jpg

From here, i get three inequalities,
f(2)<0 and f(4)>0 and D>0
Solving these inequalities, i get a can lie in interval (1,3).
But this is not the answer, the answer is (1,5)-{3}.
Then i thought that graph could be also like this:-
kb20d4.jpg

But this gives completely different set of inequalities, now i am completely stuck.

Any help is appreciated. :)

The quadratic formula simplifies the root to a function of "a", no need to use graphs, I think your right btw (1,5)-{3} is the union of (1,3) and (3,5)
 
Hey Pranav-Arora! :smile:

Pranav-Arora said:
I tried to visualize the question by graph. The graph could have been like this (this is only a rough sketch):-

Aha! You're drawing again. Good! :approve:

Solving these inequalities, i get a can lie in interval (1,3).

Yep.

Then i thought that graph could be also like this:-
But this gives completely different set of inequalities, now i am completely stuck.

Not stuck.
This is indeed another set of inequalities that you also have to solve.
The solution is the combination of both solutions.
 
hqjb said:
The quadratic formula simplifies the root to a function of "a", no need to use graphs, I think your right btw (1,5)-{3} is the union of (1,3) and (3,5)

Oh yes, i knew about it, it will reduce to (x-a)2-1=0 and then we can proceed on the next steps. Thanks for the reply! :)

Hello ILS! :smile:

The one who always helps me said:
Aha! You're drawing again. Good! :approve:
Thanks. :blushing:

I Like Serena said:
Not stuck.
This is indeed another set of inequalities that you also have to solve.
The solution is the combination of both solutions.
Now i understand it. Thanks once again! :smile:
 
find the square and solve :D
 

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