Quadratic Graph & Bouncing Ball

In summary: The coefficients for A, B, and C are all negative because they represent a decrease in energy. The initial velocity (B) is negative because it represents the ball's speed when it is initially released from the hand. The displacement (C) is negative because it represents the distance the ball has moved since the last time it was measured.
  • #1
tariel
9
0
Hi guys. I've been a lurker for a while, but I've recently become super stumped on this physics question (physics is far from my forté). I've attached the graph of my bouncing ball. First, I had to identify the coefficients and what they mean. I understand that A is acceleration, B is initial velocity, and C is displacement.

I understand that the graph is shifting, and B and C of the second bounce are not necessarily equal to those numbers. How do I find the true values of B and C for each subsequent bounce?

Homework Statement


This is my graph:
http://i.imgur.com/5pnfJY5.png

Homework Equations


Y = Ax^2 + Bx + C
y = y0 + vot + 1/2at^2

The Attempt at a Solution


For the first bounce, I was able to find the initial height by doing:
Y = Ax^2 + Bx + C, with x = 0.6 seconds
Y = -4.460(0.6)^2 + 5.425(0.6) - 0.7426
Y = 0.9068 m

And velocity:
dy/dx = 2(-4.460)x + 5.425, with x = 0.6 seconds
dy/dx = 0.073 m/s

I believe I need to find these values in order to calculate the kinetic energy before and after impacts, and finding linear momentums - I have to fill out a chart like this one for seven bounces:
MDqVQY8.png


I also have no mass for the ball, p is basically equal to the velocity. And I am told that PE must be equal to KE of the ball at the beginning and at the end of each interval of free flight.
 
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  • #2
y = Ax + Bx2
y = y'
x' = x + δ
∴ x = x' - δ

Rewrite above equation using this relationship between the two variables
 

Attachments

  • quadratic curve.jpg
    quadratic curve.jpg
    9.7 KB · Views: 863
  • #3
So the B value would stay the same?
 
  • #4
It seems so yes.
What type of detector did you use to get the data?
 
  • #5
I used a motion sensor hooked up to Logger Lite software, can't remember the exact specifics as I did the data collection some time ago.

I just want to make sure I'm doing this right, my tutor hasn't responded to me yet. So for the second bounce, using your equation, this is what I did:

Bounce 1 occurred between 0.2-0.9 seconds.
δ = 0.9 - 0.7 = 0.2
x = x' - δ
= 0.9 - 0.7
x = 0.2

Bounce 2:
y = Ax^2 + Bx
= -4.320(0.2)^2 + 12.36(0.2)
= 2.29 m ? Should this not be lower than the first bounce? (and why am I not incorporating C?)

Then
dy/dx = 2(-4.320)x + 12.36
= 2(-4.320)(0.2) + 12.36
= 10.632 m/s

I don't have a clue if I'm going about this correctly!
 
Last edited:
  • #6
So the ball was bouncing up and down while the motion sensor was looking down onto it?
This means that you have time on the x-axis and distance from the motion sensor on the y?
What are the units for each?
If the variables on the axes are y(t) then one would expect a relationship of the form:

y = yo - vot + 1/2 gt2

which does not agree with the fitted coefficients - the signs are wrong. So maybe the motion sensor's measurements was used to calculate the ball's distance from the floor. In this case one would expect

y = yo + vot - 1/2 gt2

in which case the signs of the fitted coefficients agree, but still the meaning of C0 worries me.
 
Last edited:
  • #7
Sorry, I'll go back to the beginning. I have a feeling this is simpler than what it seems, but my tutor has yet to respond to me.

Yes, the sensor was held vertically above the bouncing ball. The data collected produced this graph:

http://i.imgur.com/QSxyot1.png

y-axis is the vertical distance between the ball and the sensor, x-axis is time.

This graph was analyzed using Graphical Analysis, the y-axis was altered so it would show the ball's position relative to the ground instead of the sensor.

I did quadratic fits for each bounce interval on the new graph, which I posted earlier but I'll post it again:

http://i.imgur.com/xme9ZBP.png

After that, these were my instructions:
"Fitting the data points corresponding to each interval, using the equation Y = A t⋀2 + B t + C (see Fig 5.3). Write a clear interpretation of the meaning of each parameter in this equation.

I said that A represents acceleration, B represents initial velocity, and C represents initial position.

From the fit results of each interval, you should notice that the B parameter increases as the ball makes a new bounce! If B is interpreted as the initial velocity of the ball for the corresponding bounce, this seems to contradict the observed loss of mechanical energy after each bounce! Can you explain this apparent discrepancy?

I'm guessing it's due to the shift, but I'm not understanding these values. I don't understand why A and C are negative, why C is becoming increasingly negative, as well as what is going on with the velocity. I'm not sure how to account for these in the analysis either. The example they gave produced a graph similar to mine, with similar patterns in how the A, B, and C values increase/decrease.

And THEN I have to do this:

Using the maximum height of the ball, it should be possible to calculate its maximum potential energy (PE) in the middle of each interval. From the principle of conservation of mechanical energy, this must be equal to the kinetic energy (KE) of the ball at the beginning and at the end of each interval of free flight. Therefore, you should be able to calculate the kinetic energy per unit mass (KE/m) just before and just after each impact with the ground. The momentum per unit mass (p/m) can also be calculated just before and just after each impact. Note that this quantity is basically equal to the ball’s velocity.

After showing detailed sample calculations, construct a table similar to the one shown below, in which you include the changes in the kinetic energy and momentum as a result of each impact. Note that the momentum is a vector quantity, and therefore, the sign is very important.


Du0jh00.png


And this is where I'm trying to get the velocities... unless I don't have to and just use the B values. But I'm getting numbers that do not make sense to me.
 
  • #8
tariel said:
I'm guessing it's due to the shift,
If you mean the time shift, yes. Consider the second bounce as if it were just the top part of a single trajectory that started at time 0, i.e. about one second before any of its datapoints. Where would the trajectory have started at time 0, and with what speed?
I don't understand why A and C are negative, why C is becoming increasingly negative, as well as what is going on with the velocity.
For A, what is the cause of the acceleration? Which way does that act? Which way are you measuring Y?
For C, see my comment above on time shift.
Using the maximum height of the ball, it should be possible to calculate its maximum potential energy (PE) in the middle of each interval. From the principle of conservation of mechanical energy, this must be equal to the kinetic energy (KE) of the ball at the beginning and at the end of each interval of free flight. Therefore, you should be able to calculate the kinetic energy per unit mass (KE/m) just before and just after each impact with the ground. The momentum per unit mass (p/m) can also be calculated just before and just after each impact. Note that this quantity is basically equal to the ball’s velocity.

And this is where I'm trying to get the velocities... unless I don't have to and just use the B values. But I'm getting numbers that do not make sense to me.

You can't use the B values for the reasons given: they do not represent velocities all at the same height.
 
  • #9
I knew it was simpler than what I was doing!

Okay, so since I have max. heights for each of the bounces, I can find PE as g*h. So before impact, KE = PE. After impact, KE would be the PE of the following bounce, correct?

And since momentum is the velocity in this case (no mass was recorded), it would be:
1/2 mv^2 = mgh
v = sqrt 2*g*h

Am I correct in my thinking here?
 
  • #10
tariel said:
Okay, so since I have max. heights for each of the bounces, I can find PE as g*h. So before impact, KE = PE. After impact, KE would be the PE of the following bounce, correct?

And since momentum is the velocity in this case (no mass was recorded), it would be:
1/2 mv^2 = mgh
v = sqrt 2*g*h
Yes, that's all correct. Btw, in the graphs, something odd seems to have happened between the third and fourth bounces. It looks like the sensor got knocked down a bit.
 
  • #11
haruspex said:
Btw, in the graphs, something odd seems to have happened between the third and fourth bounces. It looks like the sensor got knocked down a bit.

Probably me! I was holding it above while simultaneously trying to make the ball bounce directly below. I'll just take note of the discrepancy in the write up, since it's basically saying the ball gained energy somehow, haha.
 

What is a quadratic graph?

A quadratic graph is a type of graph that represents a quadratic equation, which is an equation in the form of y = ax^2 + bx + c. The graph of a quadratic equation is a parabola, a U-shaped curve that can either open upwards or downwards depending on the values of a, b, and c.

How is a quadratic graph related to a bouncing ball?

A quadratic graph can be used to model the height of a bouncing ball over time. This is because the path of a bouncing ball follows a parabolic trajectory, just like the graph of a quadratic equation. The vertex of the parabola represents the maximum height of the ball, while the x-intercepts represent the times when the ball hits the ground.

What information can be determined from a quadratic graph of a bouncing ball?

From a quadratic graph of a bouncing ball, we can determine the initial height of the ball, the maximum height it reaches, the time it takes to reach the maximum height, and the total time the ball is in the air.

How can we use a quadratic graph to calculate the maximum height of a bouncing ball?

The maximum height of a bouncing ball can be determined by finding the y-coordinate of the vertex of the parabola, which can be calculated using the formula x = -b/2a, where a and b are the coefficients of the quadratic equation representing the ball's height.

What factors can affect the shape of a quadratic graph of a bouncing ball?

The shape of a quadratic graph of a bouncing ball can be affected by the initial height of the ball, the force of gravity, air resistance, and the surface it bounces on. These factors can change the values of a, b, and c in the quadratic equation and therefore alter the shape of the graph.

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