- #1

jbm1939

- 7

- 1

## Homework Statement

A ball weighing 0.2 lbs is dropped out the window of a pickup truck moving horizontally at 45 mph. If the C.O.R. (e) between the ball and the ground is equal to 0.6, find the height of the ball's first bounce and the horizontal distance it will travel before bouncing again.

**I believe i have the height of the bounce, but am stuck on how far it will travel horizontally. I'll put below what i have so far.**

**The attempt at a solution:**

mgh = 1/2mv

^{2}

V

_{f}= Square rt(2gh)

square rt(2(32.2)(5ft)

=17.9 ft/s

V

_{1}= 0.6(17.9ft/s)

= 10.76 ft/s

1/2mv

^{2}= mgh

h=v

_{i}

^{2}/ 2g

=10.76

^{2}/ 2(32.2)

=1.798 ft