Quadratic Simultaneous Equation

[fonz]

Homework Statement

Solve the equation for x

y^2 = 4x

x^2 = 4y

Homework Equations

None

The Attempt at a Solution

y^2 -4x = x^2 - 4y = 0

I have spent ages re-arranging and substituting in values but I just cannot solve this thing.

 

[CAF123]

Why don't you try to rearrange the second equation for y and sub into the first equation. This will give you an equation entirely in terms of x.

 

[fonz]

y = 2\sqrt{x}
y = \frac{x^{2}}{4}

I still have no idea how to find x

 

[Mark44]

y = 2\sqrt{x}
y = \frac{x^{2}}{4}

I still have no idea how to find x

You didn't do what CAF123 suggested, which was to solve for y in the second equation, and then substitute for y in the first equation.

You solved for y in the second equation, but then solved for y (incorrectly) in the first equation. Note that if y² = 4x, then y = 2√x is only one of two solutions.