Quantization of Klein-Gordon Field

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go quantum!
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I was reading the book written by Peskin about QFT when I found that the following equation:
[tex] (\frac{\partial}{\partial t^2}}+p^2+m^2)\phi(\vector{p},t)=0[/tex]

has as solutions the solutions of an Harmonic Oscillator.

From what I know about harmonic oscillators, the equation describing them should have, for instance in 1-d, a second derivative and squared multiplication term with respect to the same variable, let's say x.

Thanks for your kind help-
 
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In this case the variable is [itex]\phi[/itex]:
[tex] \ddot \phi = -\left(p^2 + m^2 \right) \phi[/tex]
 
So it's the classical HO's equation. Why then write [tex]\phi[/tex] in terms of ladder operators (the famous a's)?
 
It is also the quantum HO equation in the Heisenberg picture.