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Quantum attraction by exchange of particles

  1. Jul 21, 2008 #1
    hi,
    the standard (?) explanation for particle exchange to produce
    repulsion and attraction is at:
    http://math.ucr.edu/home/baez/physics/Quantum/virtual_particles.html

    this seems to me to have two problems.

    1.) in the case of repulsion beteen two electrons,
    the direction has to be fine tuned to contrive that the
    absorbing electron gets hit by the photon.
    the probability of that happening is zero.
    (the probability of a straight line eminating from a
    point hitting some other random point in 3-d space is zero)

    2.) asymetry in that one electron is an emitter and one
    is an absorber.

    3.) attraction requires quite a bit of hand waving for such a
    fundamental response (and also still requires a special fine tuning)

    how about this for an alternative:

    each particle emits virtual photons in all directions
    (i am thinking sin waves in this example)
    two electrons intereract because everything cancels out except
    for the wave between them


    ..|...|..
    -(e)=(e)- net effect: (e)=(e)
    ..|...|..


    the net affect is a photon exchanged between them and repulsion
    aka the usual feynman diagram >-<

    electron and a positive charge interact similary, but because
    of opposite charge

    ..|...|..
    -(e)0(p)- net effect: -(e)0(p)-
    ..|...|..


    the interior photon cancels to zero
    leaving a net attraction
    net efect is a feynman diagram -< >-

    its kind of like a casimir effect.

    for charge/EM the photon is like cos(q*wt + phi)
    with phi the angle of emmission.
    looking along the x-axis
    for two charges q1 and q2
    to the left
    left=cos(q1 wt + pi ) + cos(q2 wt + pi)
    in the middle
    middle=cos(q1 wt + 0) + cos(q2 wt + pi)
    to the right
    right=cos(q1 wt + 0) + cos(q2 wt + 0)

    if(q1 == q2) {
    then left=0; right=0;
    and there is an exchange of
    photons in the middle = repulsion}

    if(q1 == -q2){
    then left=-2cos(qwt);right=2cos(qwt);
    middle=0;
    =attraction
    }

    even more speculative, if you say the phase of the
    photon is somehow a property of the spin , this could
    also explain why gravity is always attractive

    what do you think? crazy? already done?
    i should go back to work?

    yoyoq
     
  2. jcsd
  3. Jul 22, 2008 #2
    i think i have a sign wrong in my math, but you get the idea (i hope)
     
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