Quantum Dynamics: Boron 14 Splitting into Carbon 14 and Electron

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SUMMARY

The discussion focuses on the quantum dynamics of a boron-14 nucleus splitting into carbon-14 and an electron. The conservation of momentum and energy are critical principles in solving this problem, with specific equations such as E^2 = p^2c^2 + m^2c^4 being essential. The participant seeks guidance on applying these equations to determine the speeds and kinetic energies of the resulting particles. The solution involves calculating momentum and energy while considering the relativistic effects due to the mass differences between the carbon and electron.

PREREQUISITES
  • Understanding of conservation of momentum and energy in quantum physics
  • Familiarity with relativistic equations, particularly E^2 = p^2c^2 + m^2c^4
  • Knowledge of kinetic energy definitions, including KE = Ymc^2 - mc^2
  • Basic concepts of particle physics, specifically regarding nuclear decay
NEXT STEPS
  • Study the relativistic dispersion law in detail
  • Learn how to apply conservation laws in particle decay scenarios
  • Explore the concept of gamma (γ) in relativistic physics
  • Investigate the differences in kinetic energy calculations for particles of varying masses
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Students and enthusiasts of quantum physics, particularly those interested in nuclear decay processes and relativistic mechanics.

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Homework Statement



a boron 14 nucleus (mass=14.02266u) is at rest splits into a electron (.00055U) and a carbon 14 (13.99995u) what are the speeds and KE for the carbon and the electron.

Homework Equations



i need help getting started on this so could someone help me get started.



The Attempt at a Solution

 
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What you need is: conservation of momentum, conversation of energy (both together correspond to conservation of 4 Momentum)
then you need the relativistic Dispersion law:
E^2-\vec{p}^2=m^2
and the definition of kinetic energy:
E_{kin}=E-m
If you use all that and convert your units the right way you are done.
 
the only equations my book gave me are;
p=Ymu
E=Ymc^2
KE=Ymc^2-mc^2
KE=mc^2+1/2mu^2
deltaKE+delta mc^2
E^2=p^2C^2+m^2C^4
so i don't know if i could rewrite those equations to get the ones you told me to use. if i can can you show me how? if not can you show me how to solve the problem using those equations? I'm sorry if i seem like i don't know much but i have a quantum physics book and I'm trying to teach myself quantum physics.
 
Ok, I'll try to give a few hints:

You know that the boron was at rest, before the decay, that means by conservation of momentum:
\vec{p_C}=-\vec{p_e}
this means especially, that the momenta of carbon and electron have the same absolute value.
Since the energy is conserved (and we know the Boron was at rest, which means it had only it's rest Energy E=m_B c^2):
m_B c^2=E_e+E_C
now you plug in E^2=p^2c^2+m^2c^4 for e and C and use that the momentum for e and C hast the same absolute value(which I will denote by p):
m_B c^2 =2 p^2 c^2 +(m_e^2+m_C^2)c^4
Now you can use this to find p^2, since you now all the other quantities. then you plug this into:
p^2=\gamma^2 m^2 v^2
now you can plug in the formula for gamma and find v. (the speeds will be different for electron and Carbon since they have different masses).
To find E_{kin} you just plug p into E^2=p^2c^2+m^2c^4 for the electron and the Carbon, take the square root of it and substract m c^2 to get the kinetic energy
 
thanks that makes sense but what dose the arow above pc mean?
 
The arrow means that its a vector.
 
ok thanks that helped a lot
 

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