Quantum efficiency as a function of wavelength

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SUMMARY

The discussion focuses on calculating quantum efficiency as a function of wavelength using band-gap energies for materials such as GaInP, GaAs, and Ge. The user applied the formula Energy(eV) = 1240/wavelength(nm) to derive corresponding wavelengths: 670 nm for GaInP, 873 nm for GaAs, and 1851 nm for Ge. However, the user seeks a more comprehensive quantum mechanical approach to accurately plot quantum efficiency. The relevant equations discussed include E=hν and E=hc/λ.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically energy-wavelength relationships.
  • Familiarity with band-gap energies of semiconductor materials.
  • Knowledge of the Planck constant and its application in quantum calculations.
  • Basic proficiency in using mathematical formulas for physics-related computations.
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  • Research quantum efficiency calculations in semiconductor physics.
  • Explore advanced quantum mechanics formulas related to energy and wavelength.
  • Learn about the role of band-gap energies in determining material properties.
  • Investigate graphical representation techniques for quantum efficiency plots.
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Physicists, materials scientists, and engineers involved in semiconductor research and development, particularly those interested in quantum efficiency and optical properties of materials.

gnurf
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I'm trying to reproduce the plot in the attached figure. I know the band-gap energies, so I was hoping there was some simple way I could get the quantum efficiency as a function of wavelength. I read on wiki that Energy(eV) = 1240/wavelength(nm), so I mechanically plugged those in, and got

GaInP (Eg=1.85eV): 670 nm
GaAs (Eg=1.42eV): 873 nm
Ge (Eg=0.67eV): 1851 nm

Other than that the respective wavelengths came out in the right order, it didn't really help all that much. Is there some magical quantum mechanical formula I could drink in order to make that plot?

VthIs.png


EDIT: I should probably have posted this in the QM sub-forum. My apologies.
 
Last edited:
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E=h[itex]\upsilon[/itex]
E=[itex]\frac{hc}{\lambda}[/itex]
E=[itex]\frac{h\ =\ 4.135\ \times\ 10^{-15}\ eV\ s\\times\ 3\ \times\ 10^{17}\nm}{\lambda}[/itex]
E=[itex]\frac{1240}{\lambda}[/itex]
 

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