The element N has 7 electrons and 7 protons in the atom. An ion of N has all the electrons removed except 1, so it resembles a hydrogen atom with a nuclear charge of +7 e.
E1(Hydrogen)= -13.6eV, r1(Hydrogen)= 5.29x10^-11m.
k = 8.99x10^9 e = 1.6x10^-19
What is the total energy (in eV) of the lowest energy state available to the ion?
E = -((k*e^2)/(2r))
The Attempt at a Solution
It's been driving me insane! I've put every single combination of variables into the equation, and nothing is coming out correctly. They're all in order of magnitudes wrong, so I think I might be using the wrong constants/variables, or even the wrong equation. Can anyone point me in the right direction, as to what I should be putting where? Thanks!