Quantum Mechanics and Eigenfunctions Checks

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TFM
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Homework Statement



For each of the following wave functions check whether they are eigenfunctions of the momentum operator, ie whether they satisfy the eigenvalue equation:

[tex]\hat{p} \psi(x) = p\psi(x) with \hat{p} = i \hbar \frac{\partial}{\partial x}[/tex] and p is a real number.

For those that are eigenfunctions, calculate the eigenvalue p, the expectation value〈[tex]\hat{p}[/tex]〉, and the standard deviation Δ[tex]\hat{p}[/tex] ̂.

(a)

[tex]\psi(x) = \sqrt{\frac{2}{L}} cos(\frac{x\pi}{L}) for -L/2 \leq x \leqL/2[/tex]

0 for x > L/2, x < -L/2

(b)

[tex]\phi(x)= \frac{1}{\sqrt{L}}e^{ikx} for 0 \leq x \leq L with k is real [\tex]<br /> <br /> 0 for x > L, x < 0<br /> <br /> <br /> (c)<br /> <br /> [tex]\chi (x) = 2xe^{-x} for 0 \leq x[/tex]<br /> 0 for x < 0<br /> <br /> <br /> <h2>Homework Equations</h2><br /> <br /> N/A<br /> <br /> <h2>The Attempt at a Solution</h2><br /> <br /> Okay, I have gone some way through the first part.<br /> <br /> [tex]\hat{p} = -i \hbar \frac{\partial}{\partial}[/tex]<br /> <br /> [tex]-i\hbar \frac{\partial}{\partial x}(\sqrt{\frac{2}{L}}cos\frac{x\pi}{L})[/tex]<br /> <br /> [tex]-i\hbar \sqrt{\frac{2}{L}} \frac{\partial}{\partial x}(cos\frac{x\pi}{L})[/tex]<br /> <br /> With Limits between L/2 and -L/2<br /> <br /> [tex]-i\hbar \sqrt{\frac{2}{L}} (-\frac{\pi}{L}sin\frac{x\pi}{L})^{L/2}_{-L/2}[/tex]<br /> <br /> [tex]-i\hbar \sqrt{\frac{2}{L}} ([-\frac{\pi}{L}sin\frac{L\pi}{2L}]-[-\frac{\pi}{L}sin\frac{-L\pi}{2L}])[/tex]<br /> <br /> [tex]-i\hbar \sqrt{\frac{2}{L}} ([-\frac{\pi}{L}sin\frac{\pi}{2}]-[-\frac{\pi}{L}sin\frac{-\pi}{2}])[/tex]<br /> <br /> But I am unsure where I am supoosed to go from here...<br /> <br /> To show it is a Eigenfunction, I need to get rid of the i at the very begining, but I am unsure how to do this?<br /> <br /> Any suggesstions where to rpoceed?<br /> <br /> Thanks in advance,<br /> <br /> TFM[/tex]
 
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You do not need the boundary conditions to check if a function is an eigenstate so no need to replace x by L/2 or -L/2. These limits only enter when you calculate the expectation values.


You must ask yourself if the function you get after applying [itex]i \hbar \partial_x[/itex] to [itex]\psi[/itex] is proportional to the wavefunction itself. If yes, then the wavefunction is an eigenstate and the constant of proportionality is the eigenvalue. If not, the function is not an eigenstate.
 
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So do I need to differnitiate it then?
 
TFM said:
So do I need to differnitiate it then?

Yes. Sorry, there was a typo in my post and the partial derivative did not show up. Yes, you must apply [itex]i \hbar \partial_x[/itex] to [itex]\psi[/itex] and check if the result is proportional to the wavefunction itself. Is it possible to write [itex]\sin(\pi x/l)[/itex] as a constant times [itex]\cos (\pi x/L)[/itex] in such a way that the result will be valid for any value of x ? If the answer is no, then this wavefunction (the cos) is not an eigenstate of the momentum operator
 
Okay so the original wavefunction is:

[tex]\psi(x) = \sqrt{\frac{2}{L}} cos(\frac{x\pi}{L})[/tex] --- (1)

The [tex]\hat{p}[/tex] function is:

[tex]-i\hbar \sqrt{\frac{2}{L}} (-\frac{\pi}{L}sin\frac{x\pi}{L})[/tex] Which can be simplified to:

[tex]i\hbar \sqrt{\frac{2}{L}} * \frac{\pi}{L}sin\frac{x\pi}{L}[/tex]

So now I have to see if this result is proportional to (1).

So I have to find how to write [tex]sin(\frac{\pi x}{L})[/tex] as [tex]C cos(\frac{\pi x}{L})[/tex]

Can this actually be done, though, since the only relation I know that will link sin and cos is [tex]sin^2(\theta) + cos^2(\theta) = 1[/tex]?

Also, do I need to get rid of that i at the beginning, since p needs to be a real number?