Quantum mechanics hermite polynomials

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SUMMARY

The discussion focuses on transforming the one-dimensional Schrödinger equation into a form solvable by Hermite polynomials. The transformation involves substituting variables and manipulating the equation to yield a standard form, specifically achieving the equation (d²/dξ²)ψ + (λn - ξ²)ψ = 0, where λn = 2n + 1. Key steps include substituting ξ = x√(mω/ħ) and using the relation dHn(X)/dX = 2nHn(x) to derive solutions that converge at infinity. The final form allows for the identification of Hermite polynomial solutions corresponding to quantum states.

PREREQUISITES
  • Understanding of the Schrödinger equation in quantum mechanics
  • Familiarity with Hermite polynomials and their properties
  • Knowledge of variable substitution techniques in differential equations
  • Basic concepts of quantum harmonic oscillators
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  • Study the derivation of Hermite polynomials and their applications in quantum mechanics
  • Learn about the quantum harmonic oscillator model and its significance
  • Explore the method of Frobenius for solving differential equations
  • Investigate the physical implications of energy quantization in quantum systems
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Students and researchers in quantum mechanics, physicists focusing on wave functions, and anyone interested in the mathematical foundations of quantum theory.

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Homework Statement


Show that the one-dimensional Schr¨odinger equation
ˆ
(p^2/2m) ψ+ 1/2(mw^2)(x)ψ = En ψ
can be transformed into
(d^2/d ξ ^2)ψ+ (λn- ξ ^2) ψ= 0 where λn = 2n + 1.
using hermite polynomials


Homework Equations



know that dHn(X)/dX= 2nHn(x)

The Attempt at a Solution


I don't know how to start this question off at all
 
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The question is a bit unclear to me. If I understand it correctly you should do the following:
1. get the first equation to the form
[tex]$ d^2\psi/dx^2 + 2m/\hbar^2(E-m\omega^2 x^2/2) \psi = 0$[/tex]
2. substitute [tex]$ \xi = x \sqrt{m\omega/\hbar}$[/tex]
3. you should get
[tex]$ d^2\psi/d\xi^2 + (2E/\hbar \omega - \xi^2) \psi = 0$[/tex]
4. now substitute [tex]$\psi = \varphi(\xi) \exp(-\xi^2/2)$[/tex] to get
5. [tex]$ d^2\varphi/d\xi^2 - 2\xi d\varphi/d\xi + (2E/\hbar\omega-1)\varphi = 0$[/tex]
This equation has solutions that diverge at infinity not faster than a polynomial - Hermite polynomials - only when [tex]$ 2E/\hbar\omega-1 = 2n$[/tex], where [tex]$ n = 0,1,2,...$[/tex]

Hope that helps!
 
Hey that's perfest thanks was stuck on how to get ξ into the equation.
 

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