Showing f is a solution to quantum oscillator SWE

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SUMMARY

The discussion focuses on proving that the function fn = xψn + ħ/mω ∂xψn is a solution to the low energy Schrödinger Wave Equation (SWE) for a 1-dimensional simple harmonic oscillator. The Hamiltonian operator is defined as H = -ħ²/2m ∂xx + 1/2 mω²x², and it is established that Hfn = (En - ħω)fn must hold true. The wave function ψn is expressed as ψn = Cne^(-mωx²/2)Hn(x), where Hn(x) represents the nth order Hermite Polynomial. The solution requires applying the Hamiltonian operator to fn and simplifying the resulting expression.

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Homework Statement


For a 1-dimensional simple harmonic oscillator, the Hamiltonian operator is of the form:
H = -ħ2/2m ∂xx + 1/2 mω2x2
and
n = Enψn = (n+1/2)ħωψn

where ψn is the wave function of the nth state.

defining a new function fn to be:

fn = xψn + ħ/mω ∂xψn

show that fn is a solution to the low energy SWE. I.e. that:

Hfn = (En - ħω)fn

The Attempt at a Solution


I know that:
ψn = Cne-mωx2/2Hn(x)
where Hn(x) is an nth order Hermite Polynomial.
I was wondering what the procedure for determining this would be. I'm assuming I could plug this expression for ψn into the expression for fn, and then apply the Hamiltonian operator. But I'm not sure how that would simplify, and it also seems very complicated to plug in. Any help would be appreciated
 
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I believe you are meant to let the operator H act on the expression for fn and show that Hfn reduces to (En - ħω)fn.

It will require a fair amount of manipulation and use of the fact that Hψn = Enψn. But nothing else is needed.
 
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