Quantum mechanics wave function

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Discussion Overview

The discussion revolves around calculating the modulus squared of a quantum mechanics wave function for a particle in an infinite potential square well. The focus is on the mathematical manipulation of the wave function, specifically how to handle complex numbers and their conjugates in this context.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a wave function and seeks to calculate its modulus squared, |\Psi(x,t)|^{2}.
  • Another participant suggests using the identity e^{iz} = cos(z) + i·sin(z) as a potential approach.
  • There is a clarification that multiplying the wave function by its complex conjugate will yield |\Psi(x,t)|^{2}.
  • A participant expresses confusion about the presence of imaginary units (i's) in the resulting equation after multiplication by the complex conjugate.
  • It is confirmed that simplifying the expression should indeed eliminate the imaginary units.
  • A later reply reiterates that multiplying by the conjugate is a valid method for finding the modulus squared of any complex number.

Areas of Agreement / Disagreement

Participants generally agree on the method of using the complex conjugate to find |\Psi(x,t)|^{2}, but there is uncertainty regarding the simplification process and the presence of imaginary units in the final expression.

Contextual Notes

There are unresolved aspects regarding the simplification steps and the handling of complex numbers, which may depend on the participants' familiarity with algebraic manipulation in complex analysis.

gotmilk04
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Homework Statement


One of the quantum mechanics wave functions of a particle of unit mass trapped in an infinite potential square well of width 1 unit is given by

Ψ(x,t)= sin(\pix)e^{-i(\pi^2\overline{h}/2)t} + sin(2\pix)e^{-i(4\pi^2\overline{h}/2)t}\

where \overline{h} is a certain constant. Calculate |\Psi(x,t)|^{2}

Homework Equations





The Attempt at a Solution


I know to calculate |\Psi(x,t)|^{2} I need to separate the real and imaginary parts, but I'm not sure how to get started.
 
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Use eiz = cos(z) + i·sin(z)

Alternatively, you could multiply ψ by its complex conjugate.
 
If I multiply by the complex conjugate, I'll get |\Psi(x,t)|^{2}?
 
I multiplied it by the complex conjugate, but there are still i's in the equation. Aren't there supposed to be no i's?
 
That's right. If you multiply by the conjugate and simplify, there should be no i's left.

Show us your calculations.
 
Sorry about not responding sooner. Somehow I missed seeing this thread's new activity in my subscribed threads lists, until just now.

gotmilk04 said:
If I multiply by the complex conjugate, I'll get |\Psi(x,t)|^{2}?
Yes. This is true of any complex number.

Let z = x + iy, where x and y are real.

Then

z·z* = (x + iy)·(x - iy) = [algebra left as an exercise to the reader] = |z|2

If you post your calculation, we can help either spotting an error or with how to simplify your expression further.
 

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