(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

[tex]f(x)=x^{2}+ax+b[/tex]

If v is one root of the quadratic then [tex]v^{2}-2[/tex] is the second root. Find all possible ordered pairs (a,b). Universal set is the set of real numbers.

3. The attempt at a solution

[tex]-a=v^{2}+v-2[/tex]

[tex]0=v^{2}+v+a-2[/tex]

By putting discriminant >=0

I get:

1-4(a-2)>=0

But in the case of product of roots I get a cubic!!!

Please help me with this. How can I get th exact ordered pairs??

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# Homework Help: Quaratic Equation (roots and coefficients)

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