I Quasi-Static Change of Event Horizon Area

ergospherical
Science Advisor
Homework Helper
Education Advisor
Insights Author
Messages
1,097
Reaction score
1,384
Let ##\mathscr{H}## be a constant-##v## cross-section of the event horizon (area ##A##). The expansion is the fractional rate of change of the surface element, ##\theta = \frac{1}{\delta S} \frac{d(\delta S)}{dv}##. The problem asks to prove the formula ##\frac{dA}{dv} = \frac{8\pi}{\kappa} \oint_{\mathscr{H}} (\frac{1}{8\pi} \sigma^2 + T_{ab} \xi^a \xi^b) dS## where ##\xi## is the tangent to the null generators.

I used the Raychaudhuri equation to write down\begin{align*}
\oint_{\mathscr{H}} \left( \frac{1}{8\pi} \sigma^2 + T_{ab} \xi^a \xi^b \right) dS &= \frac{1}{8\pi} \oint_{\mathscr{H}} \left(\kappa \theta - \frac{1}{2} \theta^2 - \frac{d\theta}{dv} \right) dS \\ \\
&= \underbrace{\frac{\kappa}{8\pi} \frac{d}{dv} \oint_{\mathscr{H}} dS}_{= \frac{\kappa}{8\pi} \frac{dA}{dv} } - \frac{1}{8\pi} \oint_{\mathscr{H}} \left( \frac{1}{2} \theta^2 + \frac{d\theta}{dv} \right) dS
\end{align*}I suppose the quasi-static approximation is supposed to kill the other term but I'd like to justify it properly?
 
Physics news on Phys.org
As I suggested in another one of your questions, you should really provide a reference.
Your homework question is
not self-contained.

For the possibly interested reader, what is \kappa, \sigma,…,etc?

If the question was only intended for those already familiar with the situation, then this should be classified as A-level, not I-level.
 
  • Like
Likes ergospherical
Sorry, the question is the last one in the Black Hole section of E. Poisson's relativist's toolkit. ##\kappa## is the surface gravity, ##\sigma^2 = \sigma^{ab}\sigma_{ab}## the square of the shear, ##v## the parameter along the null generators and ##dS = \sqrt{^2g} d^2 \theta## the surface element on ##\mathscr{H}## with ##(^2g)_{ab} = \frac{\partial x^{c}}{\partial \theta^a} \frac{\partial x^d}{\partial \theta^b} g_{cd}## the pull-back of ##g## onto ##\mathscr{H}##.
 
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...

Similar threads

Back
Top