Graduate Query about an article on quantum synchronization

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The discussion centers on a paper about quantum synchronization, specifically addressing the implications of U(1) symmetry on observable quantities. It explains that due to this symmetry, the expectation values of raising and lowering operators are zero, leading to the conclusion that all nonzero observables must be expressible in terms of specific operators. The relevant operators include the expectation values of the z-component and products of raising and lowering operators, which do not yield zero. This understanding is crucial for analyzing the behavior of ensembles in quantum systems. The inquiry seeks clarification on why these specific terms encompass all nonzero observables.
Danny Boy
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Query in attached paper on quantum synchronization.
I am currently studying this paper on quantum synchronization. The first page gives an introduction to synchronization and the basic setup of the ensembles in the cavity. My query is on the second page where the following statements are made.

Because of the ##U(1)## symmetry, ##\langle \hat{\sigma}^{\pm}_{(A,B)j} \rangle = 0##. Therefore, all nonzero observables can be expressed in terms of ##\langle \hat{\sigma}^{z}_{(A,B)j} \rangle, \langle \hat{\sigma}^{+}_{(A,B)i}\hat{\sigma}^{-}_{(A,B)j} \rangle## and ##\langle \hat{\sigma}^{z}_{(A,B)i}\hat{\sigma}^{z}_{(A,B)j} \rangle.##

Can anyone see why the implication is that all observables can be expressed by these terms?

Thanks for any assistance.
 

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The statement is referring to the fact that, due to the ##U(1)## symmetry, the expectation values of the raising and lowering operators are zero. This means that any observables that can be expressed in terms of these operators will also have zero expectation values. As such, the only nonzero observables are those that can be expressed in terms of the ##\langle \hat{\sigma}^{z}_{(A,B)j} \rangle, \langle \hat{\sigma}^{+}_{(A,B)i}\hat{\sigma}^{-}_{(A,B)j} \rangle## and ##\langle \hat{\sigma}^{z}_{(A,B)i}\hat{\sigma}^{z}_{(A,B)j} \rangle## operators, as these are the only ones which do not contain raising or lowering operators.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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