Question about a derivation of jackson

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SUMMARY

The discussion centers on the derivation of photon incidence rates as presented in Jackson's "Classical Electrodynamics." Specifically, it addresses the calculation of the number of photons striking a 1 square centimeter area per second from a 100W bulb and an FM antenna operating at 100W and 10^8 Hz. The key formula involves calculating intensity by dividing power by the surface area of a sphere with a 1 m radius, followed by multiplying the intensity by the area and dividing by the energy of a single photon, defined by E = hf.

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  • Understanding of electromagnetic theory
  • Familiarity with the concept of photon energy (E = hf)
  • Knowledge of intensity calculations in physics
  • Basic grasp of spherical geometry for surface area calculations
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  • Explore the relationship between power, intensity, and photon flux
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  • Investigate Jackson's "Classical Electrodynamics" for further examples and applications
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in the introduction to jackson's classical electrodynamics, he states that the number of photons incident to a 1 square centimeter area in 1 s for a 100W bulb (1 m away) is on the order of 10^15.

also he gives a similar quantity for an FM antenna operating at 100W at a frequency of 10^8 Hz.

what's the derivation for these numbers?

I suspect that you need to find the intensity of the beams, then multiply by the 1 cm square to get the total energy - and then divide by the energy of 1 photon ( given by E = hf ).

what I don't know is how to get the intensity.
 
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The intensity is the power (given) divided by the surface area of a sphere 1 m in radius.
 

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