Question About a Test Charge Near a Conductor

AI Thread Summary
The discussion centers on the confusion regarding the method of charging a conductor through induction and the concept of equilibrium in the system. It clarifies that reaching equilibrium is essential, as charge will continue to flow until this state is achieved. The participants express uncertainty about the terminology used, particularly regarding the equivalence of electric fields. Additional steps in the charging process are noted as necessary for a complete understanding. Overall, the conversation highlights the complexities of electrostatics and the nuances of charging conductors.
nmfowlkes
Messages
3
Reaction score
0
Homework Statement
A positive test charge is brought near to, but not touching, a conducting sphere that is connected to the ground. Both objects remain at rest in the positions shown above. Charge begins to flow from the ground to the sphere. Which of the following statements best describes when charge stops flowing, and provides justification for the claim?

A. Charge will flow until the electric field at the surface of the sphere is equivalent to the electric field of the test charge, because then the excess charge on the surface of the sphere will be equal to the charge of the test charge.

B. Charge will flow until the electric field at the surface of the sphere is equivalent to the electric field of the test charge, because then the net force on all charges on the surface of the sphere will be zero.

C. Charge will flow until the potential at the surface of the sphere is the same as the potential of the test charge, because then the net force on all charges on the surface of the sphere will be zero.

D. Charge will flow from the ground to the sphere until the potential is the same everywhere within the sphere, because then the excess charge on the surface of the sphere will be equal to the charge of the test charge.

E. Charge will flow from the ground to the sphere until the potential is the same everywhere within the sphere, because then the net force on all charges on the surface of the sphere will be zero.
Relevant Equations
This is a conceptual problem. Equations are not relevant.
I am confused because I thought this was a method of charging a conductor. Why would the system be reaching a state of equilibrium?
 
Physics news on Phys.org
You bring up the charge and then count to ten...Equilibrium for as long as you keep the test charge stationary . What does it look like and why?
 
nmfowlkes said:
I am confused because I thought this was a method of charging a conductor.
It is only part of the method of charging a conductor by induction. There are additional steps which are not taken here.
nmfowlkes said:
Why would the system be reaching a state of equilibrium?
Because if it is not in equilibrium, charge will flow until it reaches equilibrium.

The wording in the first two choices bothers me. I don't know how to tell that an electric field is "equivalent" to another electric field. Is this something that is discussed in wherever you found this question?
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top