- #1
juaninf
- 27
- 0
Let [tex]G[/tex] group and [tex]N[/tex] subgroup normal from [tex]G[/tex] if [tex]b \in{G}[/tex] and [tex]p[/tex] is prime number then [tex](Nb)^p=Nb^p[/tex],
Please help me with steps to this proof.
Please help me with steps to this proof.