- #1
Blairmc2
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Q.
A 0.150 kg billiard ball (A) is rolling toward a stationary billiard ball (B) at 10.0 m/s. After the collision, ball A rolls off at 7.7 m/s at an andle of 40.0 degrees clockwise from its original direction. What is the speed and direction of Ball B after the collision?
Known:
M of A = .150 kg
M of B = .150 kg
Vi of B = 10.0 m/s
Vf of A = 7.7 m/s[70degrees clockwise]
Implied:
Vi of A = 0 m/s
Ff = 0N
Unknown:
Vi of B = ?
I started out using the law of conservation of energy but I messed up somewhere early and got fully lost...I know you need to use this method to conserve the momentum of each object but I just can't remember how, can someone start please?
A 0.150 kg billiard ball (A) is rolling toward a stationary billiard ball (B) at 10.0 m/s. After the collision, ball A rolls off at 7.7 m/s at an andle of 40.0 degrees clockwise from its original direction. What is the speed and direction of Ball B after the collision?
Known:
M of A = .150 kg
M of B = .150 kg
Vi of B = 10.0 m/s
Vf of A = 7.7 m/s[70degrees clockwise]
Implied:
Vi of A = 0 m/s
Ff = 0N
Unknown:
Vi of B = ?
I started out using the law of conservation of energy but I messed up somewhere early and got fully lost...I know you need to use this method to conserve the momentum of each object but I just can't remember how, can someone start please?