Question about cross and dot product

[leonne]

Homework Statement

Note: \nu is del could not find it...

I need to prove the \nu*E=0
and \nu x E=-dB/dt

Homework Equations

E(s\phizt)=(Acos(Kz=wt)/s)s^

The Attempt at a Solution

so for the first one \nu*E=0 I thought it would be
d/ds(E) but what they did was 1/s d/ds(s E) no idea why they did it. Is it because its S^? I thought i remember doing something like this.
for the cross product
d/ds d/d\phi d/dz
E 0 0

...I got the right answer but they got 0+dE/dZ \phi^-1/s dE/d\phi z^
no idea how they got the z^ i thought it was 0, well it does =0 but where did the -1/s come from?
thanks for the help[STRIKE][STRIKE][/STRIKE][/STRIKE]

 

[lanedance]

try writing all youyr code in a single tex banner & to write del (\nabla), so you want to show:
\nabla \bullet E = 0

how about directly applying the product? I can;t really understand the form of your electric field - mayeb you can re-write it?

 

[leonne]

hmm can't edit my post
so need to show that
\nabla \bullet E=0
\nabla \times E= -dB/dT
Well its a wave function
And i need to show that E satisfy Maxwell equation and the boundary conditions.
boundary condition E parallel =0 and B perpendicular=0
lets say E was x^ for the dot product
(d/dx+d/dy+d/dz)(E x^+0+0) so i would have dE/dx am i wrong?