Question about Feynman diagram showing annihilation

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SUMMARY

The discussion centers on the interpretation of a Feynman diagram depicting annihilation, specifically the role of the middle line with an arrow pointing to the right. Participants clarify that this line represents an electron, not a W boson, as a W-line would violate Lorentz symmetry and electroweak gauge symmetry. The consensus is that the horizontal line cannot be removed without losing essential information about the interaction, which includes conservation of energy and momentum.

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songoku
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Homework Statement
Please see below
Relevant Equations
Feynman Diagram
1713001049977.png


This is Feynman diagram of annihilation I get from wikipedia
https://en.wikipedia.org/wiki/Annihilation

I don't understand what the middle line with arrow to the right is. If I consider the left vertex and conservation of charge, it means the horizontal line with arrow to the right should carry negative charge. So it is W-?

Thanks
 
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It is an electron line.

A W-line would violate both Lorentz symmetry and electroweak gauge symmetry.
 
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Orodruin said:
It is an electron line.

A W-line would violate both Lorentz symmetry and electroweak gauge symmetry.
Can the horizontal line be removed so the diagram only shows two lines (one for electron and one for positron) and two photons?

Thanks
 
songoku said:
Can the horizontal line be removed so the diagram only shows two lines (one for electron and one for positron) and two photons?

Thanks
No, absolutely not.
 
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Orodruin said:
No, absolutely not.
Is the reason related to post #2? And maybe also related to conservation of energy and momentum?

Thanks
 

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