Q: A stone is thrown vertically upwards with initial speed of 5 m/s from edge of a cliff 30 m high. Find the time needed for the stone to reach the ground (in seconds).
1. (h= Vo t - 0.5 g t^2)
2. Quadratic equation:
The Attempt at a Solution
First I will use this equation: (h= Vo t - 0.5 g t^2)
-30 = (5) t - 5 t^2
Now I divide by 5 and it will be like this
t^2 - t - 6
Then, I use the quadratic equation
The answer is 3, is that right?
Another question, I am not sure..
maybe I need to calculate the upward vertical distance it will go first.. then I sum it with the actual height which is 30 m?