Question about freely falling objects

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SUMMARY

The discussion centers on calculating the time it takes for a stone, thrown vertically upwards with an initial speed of 5 m/s from a height of 30 m, to reach the ground. The equation used is h = Vo t - 0.5 g t², leading to the quadratic equation t² - t - 6 = 0. The solution confirms that the time required for the stone to hit the ground is 3 seconds, with participants agreeing on the calculations and methodology employed.

PREREQUISITES
  • Understanding of kinematic equations, specifically h = Vo t - 0.5 g t²
  • Familiarity with quadratic equations and their solutions
  • Knowledge of gravitational acceleration, typically approximated as 10 m/s²
  • Basic algebra skills for manipulating equations
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  • Review the derivation of kinematic equations for vertical motion
  • Practice solving quadratic equations using the quadratic formula
  • Explore the effects of varying initial velocities on projectile motion
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of projectile motion and kinematics.

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Homework Statement


Q: A stone is thrown vertically upwards with initial speed of 5 m/s from edge of a cliff 30 m high. Find the time needed for the stone to reach the ground (in seconds).


Homework Equations


1. (h= Vo t - 0.5 g t^2)
2. Quadratic equation:
3ea647783b5121989cd87ca3bb558916.png



The Attempt at a Solution


First I will use this equation: (h= Vo t - 0.5 g t^2)
-30 = (5) t - 5 t^2
Now I divide by 5 and it will be like this
t^2 - t - 6
Then, I use the quadratic equation
\frac{-(-1)+\sqrt{(-1)^2-4(1)(-6)}}{2(1)}

The answer is 3, is that right?

Another question, I am not sure..
maybe I need to calculate the upward vertical distance it will go first.. then I sum it with the actual height which is 30 m?
 
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RuthlessTB said:
The answer is 3, is that right?
Looks right to me.
 
simple calculation..
considering down as positive...
h=ut+1/2at.t
h=30 m
a= 10 m/s.s
u=-5m/s

30=-5t+5t.t
t=3 s
 
simple calculation..
considering down as positive...
h=ut+1/2at.t
h=30 m
a= 10 m/s.s
u=-5m/s

30=-5t+5t.t
t=3 s
 

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