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- Thread starter DrKareem
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- #2

cristo

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Well, firstly, post the equation you're trying to solve!

- #3

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I'm sorry, I (falsely) assumed everyone would recognize the equation i had in mind. The equation is

[tex]\frac{\partial^2 u}{\partial t} = a^2 \frac{\partial^2 u}{\partial x^2}[/tex]

With U(0,t)=0. U(L,t)= ??

[tex]\frac{\partial^2 u}{\partial t} = a^2 \frac{\partial^2 u}{\partial x^2}[/tex]

With U(0,t)=0. U(L,t)= ??

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- #4

cristo

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Anyway, I think the condition that says that at x=L the rod is insulated, means that the flux at x=L is zero; i.e.[tex]\left. \frac{\partial U}{\partial x}\right|_{x=L}=0[/tex]

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- #6

HallsofIvy

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Cristo is right. Saying that one end, x= 0, is held at 0 means, of course, U(0,t)= 0. Saying that the other end, x=L, means that

[tex]\frac{\partial U}{\partial x}(L, u)= 0[/tex]

[tex]\frac{\partial U}{\partial x}(L, u)= 0[/tex]

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